ODE of electric circuit consisting emf source, inductor and capacitor

  • #1
songoku
2,421
358
Homework Statement
Please see below
Relevant Equations
Kirchhoff Voltage Law

Integration
1736687086902.png


(a)
$$\varepsilon (t)=V_L+V_C$$
$$\varepsilon (t)=L\frac{dI}{dt}+\frac{q(t)}{C}$$
$$\varepsilon (t)=L\frac{d^2 q}{dt}+\frac{q(t)}{C}$$

(b) taking ##q(t)=e^{rt}##,
$$0=L\frac{d^2 q}{dt}+\frac{q(t)}{C}$$
$$0=L.r^2 e^{rt}+\frac{e^{rt}}{C}$$
$$0=L.r^2+\frac{1}{C}$$
$$r^2=-\frac{1}{LC}$$

Is it possible for the value of ##r## to be complex number? Thanks
 
Physics news on Phys.org
  • #2
Yes. It just means the circuit is oscillatory. Since there is no resistance it is also not dissipative and therefore has no real part.
 
  • Like
Likes FactChecker and songoku
  • #3
Orodruin said:
Yes. It just means the circuit is oscillatory. Since there is no resistance it is also not dissipative and therefore has no real part.
Ok, so ##r=\pm i\sqrt{\frac{1}{LC}}## and the general solution will be ##q(t)=a_1 e^{i\sqrt{\frac{1}{LC}}t}+a_2 e^{-i\sqrt{\frac{1}{LC}}t}## where ##a_1## and ##a_2## are constant.

Is this correct?

(c) I don't know to how relate ##\omega_o## to the equation in part (a). Is there any part of the equation actually contains ##\omega_o##?

Thanks
 
  • #4
Yes it is correct. Appropriately assigning the constants will result in a real solution. You can also rewrite in terms of sines and cosines. The natural frequency should be evident from this.
 
  • Like
Likes songoku
  • #5
Thank you very much Orodruin
 

Similar threads

Replies
3
Views
972
Replies
16
Views
1K
Replies
22
Views
1K
Replies
3
Views
796
Replies
18
Views
2K
Replies
1
Views
522
Replies
2
Views
2K
Back
Top