ODE w/ Discontinuous forcing function

In summary, the problem is to solve a differential equation using the Laplace transform, with initial conditions and a piecewise function given. The attempt at a solution involves taking the Laplace transform of both sides and using algebra to solve for Y(s). The inverse Laplace transform is then used to find the solution, y(t), which may involve partial fractions.
  • #1
riskybeats
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Homework Statement



My computer is having major issues with latex right now, so sorry for not putting it in latex format.

y'' + y' + (5/4)y = g(t)

y(0) = 0, y'(0) = 0, g(t) = piecewise function {sint, o <= t < pi; 0, t>= pi

Homework Equations



Laplace transform

The Attempt at a Solution



I can get it into the form y(s2 + s + (5/4)) = (1+e-pi*s)/(s2 + 1)

When you complete the square of the terms in front of y to the left, it's:
((s+1/2)2 + 1), which when divided into the other side is suspiciously like F(s + 1/2) where F(s) = 1/(s2 + 1), which would match the other sides nicely as well.

Unfortunately, I don't know how to do it in this form (inverting F(s-2) * F(s)(1+e-pi*s), or if I'm to do partial fractions with the right hand side.

Any suggestions? Thanks!
 
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  • #2


Hi there! Thank you for sharing your problem with us. Based on your attempt at a solution, it seems like you are on the right track. I would suggest using the Laplace transform to solve this differential equation. The Laplace transform is a mathematical tool that can be used to solve linear differential equations with constant coefficients, such as the one in your problem.

To use the Laplace transform, you will need to take the Laplace transform of both sides of the equation. This will give you an algebraic equation in terms of the transformed function, Y(s). Then, you can solve for Y(s) and use the inverse Laplace transform to find the solution, y(t).

In your problem, the Laplace transform of the left side of the equation would be (s^2 + s + 5/4)Y(s), as you have correctly identified. For the right side, you will need to use the Laplace transform of the piecewise function. You can do this by breaking the integral into two parts, one for the interval [0, pi) and one for the interval [pi, ∞). Then, you can use the Laplace transform of each part separately and add them together.

Once you have solved for Y(s), you can use the inverse Laplace transform to find the solution, y(t). This may involve using partial fractions, as you have mentioned. I would recommend checking your algebra carefully and using a table of Laplace transforms to help you with the calculations.

I hope this helps! Let me know if you have any further questions. Good luck with your problem!
 

FAQ: ODE w/ Discontinuous forcing function

What is an ODE with a discontinuous forcing function?

An ODE (ordinary differential equation) with a discontinuous forcing function is a mathematical model that describes the behavior of a system over time, where the input or driving force is not continuous. This means that the system experiences abrupt changes in the input over specific time intervals.

What are some examples of systems that can be modeled with ODEs with discontinuous forcing functions?

ODEs with discontinuous forcing functions are commonly used to model physical systems such as mechanical systems with impacts, electrical circuits with switches, and biological systems with abrupt changes in environmental conditions. They can also be applied in economics, finance, and other fields to model systems with sudden changes in external factors.

How do you solve ODEs with discontinuous forcing functions?

The solution to an ODE with a discontinuous forcing function can be found by breaking the time interval into smaller intervals, where the forcing function is continuous within each interval. The solution is then obtained by solving the ODE within each interval and connecting the solutions at the points where the forcing function changes.

What are the challenges of solving ODEs with discontinuous forcing functions?

The main challenge in solving ODEs with discontinuous forcing functions is the presence of discontinuities in the input. This can make it difficult to find a continuous solution that satisfies the ODE at all points in time. Additionally, the solution may not be unique, and there may be multiple possible solutions depending on the chosen initial conditions.

How are ODEs with discontinuous forcing functions used in scientific research?

ODEs with discontinuous forcing functions are used in scientific research to model real-world systems that experience sudden changes in input. They provide a more accurate representation of these systems and can help researchers better understand their behavior and make predictions. They are also used in control theory to design controllers that can respond to and mitigate the effects of abrupt changes in input.

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