OF2 + H2O -> O2 + 2HF What's being oxidized and what's being reduced?

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In summary, the chemical equation for the reaction OF2 + H2O -> O2 + 2HF is OF2 + H2O -> O2 + 2HF. The reactants in this reaction are OF2 and H2O, and the products are O2 and 2HF. The element being oxidized in this reaction is oxygen (O), and the element being reduced is fluorine (F). The overall change in oxidation state for oxygen is +2, and for fluorine it is -1.
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yoozername
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Homework Statement


Hi all,

I'm going back through some previous exam papers, and one of the questions is:

Use oxidation numbers to identify which substances are oxidized and which are reduced:
OF2 + H2O -> O2 + 2HF

I know the oxygen in OF2 is a special case, so to me it looks like OF2 is being oxidized, but it I don't know what's happening the H2O...

Can anyone shed any light on this please?

Thanks a lot!
 
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  • #2
Start assigning oxidation numbers.
 

FAQ: OF2 + H2O -> O2 + 2HF What's being oxidized and what's being reduced?

What is the chemical equation for the reaction OF2 + H2O -> O2 + 2HF?

The chemical equation for the reaction OF2 + H2O -> O2 + 2HF is OF2 + H2O -> O2 + 2HF.

What are the reactants and products in this reaction?

The reactants in this reaction are OF2 and H2O, and the products are O2 and 2HF.

Which element is being oxidized in this reaction?

The element being oxidized in this reaction is oxygen (O).

Which element is being reduced in this reaction?

The element being reduced in this reaction is fluorine (F).

What is the overall change in oxidation states for each element in this reaction?

The overall change in oxidation state for oxygen is +2, and for fluorine it is -1.

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