Optimization - area of rectangle

Using the perimeter condition, we can express y as y = (c-2x)/2. Substituting this into the area equation A = xy, we get A = x(c-2x)/2. To maximize this, we can take the derivative with respect to x, set it equal to 0, and solve for x. This will give us the value of x that maximizes the area, which turns out to be x = c/4. When x = c/4, the rectangle is a square and therefore the area is greatest. In summary, to show that the area of a rectangle is greatest when it is square, we can use the perimeter condition to express the area in terms of x and c,
  • #1
look416
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Homework Statement


If the perimeter of a rectangle is fixed in length, show that the area of the rectangle is greatest when it is square


Homework Equations





The Attempt at a Solution


if the perimeter is fixed in length, then 2x + 2y = c
then no idea to continue from there
 
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  • #2


Ok so far. Now you want to maximize x*y, right? Eliminate one of the variables using the perimeter condition and differentiate, etc.
 
  • #3


look416 said:

The Attempt at a Solution


if the perimeter is fixed in length, then 2x + 2y = c
then no idea to continue from there

So what is the area A in terms of x and c?
 

FAQ: Optimization - area of rectangle

1. How do you find the maximum area of a rectangle?

The maximum area of a rectangle can be found by using the formula A = l * w, where A is the area, l is the length, and w is the width. To find the maximum area, you can use calculus to find the value of l and w that will give you the highest possible area.

2. What is the relationship between perimeter and area of a rectangle?

The perimeter and area of a rectangle are related in that as the perimeter increases, the area also increases. However, the relationship is not linear and can vary depending on the dimensions of the rectangle.

3. How can optimization be applied to real-life situations involving rectangles?

Optimization can be applied to real-life situations involving rectangles in various ways, such as maximizing the area of a garden or minimizing the cost of materials for building a rectangular structure. It can also be used in engineering and design to find the most efficient dimensions for a rectangular object.

4. What is the difference between maximizing and minimizing the area of a rectangle?

Maximizing the area of a rectangle involves finding the largest possible area that can be achieved with given dimensions, while minimizing the area involves finding the smallest possible area. This can have different implications depending on the specific situation and goals.

5. Can the area of a rectangle be optimized without changing its perimeter?

Yes, the area of a rectangle can be optimized without changing its perimeter. This can be achieved by adjusting the dimensions of the rectangle while keeping the perimeter constant, such as increasing the length and decreasing the width by equal amounts.

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