Optimization Problem Solution - Checking and Verification

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In summary, the conversation includes a request for someone to check a solution to a problem, which is described in five parts with accompanying images. The solution is deemed correct with two additional suggestions. The conversation also includes a comment about the expression of h and the use of latex.
  • #1
opticaltempest
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Is anyone willing to check my solution to this problem? The problem is described on part 1 of the solution.

http://img458.imageshack.us/img458/5418/solution016dj.jpg"

http://img458.imageshack.us/img458/7669/solution025zk.jpg"

http://img458.imageshack.us/img458/6652/solution030fr.jpg"

http://img458.imageshack.us/img458/3950/solution048zi.jpg"

http://img458.imageshack.us/img458/7357/solution059yw.jpg"

Thanks
 
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  • #2
I'm getting a broken link on your page two, but it doesn't matter. Your work is fine - well laid out and correct.

Two things: 1) You can also eliminate r=0 as a solution by checking the first derivative in its vicinity. It leads to a maximum, as you might guess.

2) I'm not extraordinarily fond of the way you express h. If I were your professor, I'd ask you to clean up the arithmetic a bit - but that's your call and his.

Good job.
 
  • #3
Thanks for checking it over Diane_
 
  • #4
[tex]1/2\,{v}^{2}={\frac {{\it GM}}{y}}[/tex]
 
  • #5
[tex]\[\int \!v{dv}=-{\it GM}\,\int \!{y}^{-2}{dy}\]}[/tex]

testing out latex... ignore last two replies by me
 
Last edited:

FAQ: Optimization Problem Solution - Checking and Verification

What is an optimization problem in Calculus I?

An optimization problem in Calculus I involves finding the maximum or minimum value of a function. This can be done by setting the derivative of the function equal to zero and solving for the critical points.

How do you know if a critical point is a maximum or minimum?

To determine if a critical point is a maximum or minimum, you can use the second derivative test. If the second derivative at the critical point is positive, it is a minimum. If the second derivative is negative, it is a maximum.

What is the difference between local and global extrema?

Local extrema are the maximum or minimum values within a specific interval, while global extrema are the maximum or minimum values of the entire function. Local extrema can occur at critical points, while global extrema can occur at the endpoints of the interval.

Can optimization problems involve more than one variable?

Yes, optimization problems can involve more than one variable. In this case, the function will have multiple partial derivatives, and the critical points can be found by setting all the partial derivatives equal to zero.

What are some real-life applications of optimization problems?

Real-life applications of optimization problems include finding the maximum profit or minimum cost in business, maximizing the volume of a container, and minimizing the surface area of a product. They can also be used in engineering, physics, and other sciences to optimize various systems.

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