Optimization Set-Up: Finding Optimal Dimensions for a Rectangle with Area 64m^2

In summary, to find the dimensions of a rectangle with an area of 64m^2 and the smallest possible perimeter, the formula for perimeter is used: Perimeter=2x+2y, where x and y are the length and width of the rectangle. By setting up the equation 64=xy and solving for y, we can then plug in the value for y and find the minimum value of the perimeter function, which will give us the dimensions of the rectangle with the smallest perimeter. A visual representation of the functions for perimeter and area is also provided.
  • #1
Hollysmoke
185
0
We're doing optimization problems and I was just wondering if I set this one up right:

What are the dimensions of a rectangle with an area of 64m^2 and the smallest possible perimeter?

Area=xy
64=xy
y=64/x
Perimeter=2x+2y
= 2x+2(64/x)
= 2x+128/x
 
Physics news on Phys.org
  • #2
Simple. In this case you have just to find the minimum value of the perimeter function for values of x > 0, then you find y and have the dimensions of the rectangle with the smallest perimeter.

Anyway, here is the plot of the functions. Pink - Perimeter; Blue - Area.

http://img296.imageshack.us/img296/3231/plot553br.png
 
Last edited by a moderator:
  • #3
We just started so we're not at THAT level yet, but thanks anyways D8
 

Related to Optimization Set-Up: Finding Optimal Dimensions for a Rectangle with Area 64m^2

What is the purpose of optimization set-up?

The purpose of optimization set-up is to find the best possible solution to a problem by maximizing or minimizing a specific objective function while considering all relevant constraints.

What is the objective function in this problem?

In this problem, the objective function is to find the dimensions of a rectangle that will result in the largest area of 64m^2.

What are the constraints in this problem?

The constraints in this problem are that the rectangle must have an area of 64m^2 and the sides must be equal in length.

How do we find the optimal dimensions for the rectangle?

To find the optimal dimensions for the rectangle, we can use the formula for the area of a rectangle (length x width = area) and solve for the dimensions that will result in an area of 64m^2.

What is the significance of finding the optimal dimensions for the rectangle?

Finding the optimal dimensions for the rectangle allows us to efficiently use the given area of 64m^2 and maximize the space without violating any constraints. This can be useful in various real-world scenarios, such as designing a room or a garden with a specific area.

Similar threads

  • Calculus and Beyond Homework Help
Replies
1
Views
604
  • Calculus and Beyond Homework Help
Replies
2
Views
727
  • Calculus and Beyond Homework Help
Replies
5
Views
1K
  • Calculus and Beyond Homework Help
Replies
2
Views
644
  • Calculus and Beyond Homework Help
Replies
14
Views
692
  • Calculus and Beyond Homework Help
Replies
25
Views
728
  • Calculus and Beyond Homework Help
Replies
1
Views
715
  • Calculus and Beyond Homework Help
Replies
12
Views
1K
Replies
5
Views
1K
  • Calculus and Beyond Homework Help
Replies
14
Views
1K
Back
Top