Orthotropic materials defined by 9 constants

In summary, the orthotropic material constants are determined by the symmetry of the material. The stress-strain relationship is tensor in nature, and the number of independent material constants reflects the amount of symmetry. The linear elasticity section of the link you provided explains how the tensors can be written more compactly. Once you understand these relationships, a book may be needed to cover more details of the orthotopic material constants.
  • #1
johnjaypl
9
0
Could some one explain, or give me a pointer to a good explanation, of how the nine constants that are often used to define orthotropic materials are determined.

I understand what E is in each direction.

I understand poisson ratio.

I sort of understand G. (I understand it as the E equilivent for shear- is that right)

I don't understand D1111, D2222, etc.

I seam especially confused by G12, G13, and G23.

Thanks,

John
 
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  • #2
If I understand what you are asking, the number of independent material constants reflect the amount of symmetry in the material.

Most generally, the stress-strain relationship is tensor in nature:
[tex] \boldsymbol{\sigma} = \mathsf{c}:\boldsymbol{\varepsilon}[/tex]

It's important to realize that the stress and strain terms themselves can be applied not only to mechanical behavior, but electrodynamic as well via, for example, the Maxwell stress tensor.

writing it out explicitly:

[tex] \sigma_{ij} = c_{ijk\ell}~ \varepsilon_{k\ell} [/tex]

For mechanics, given a material with *no* symmetry,the 9 stress components are related to the 9 strain components via a 81-component tensor.

Symmetry reduces the number of independent components of the 4th rank tensor.

http://en.wikipedia.org/wiki/Orthotropic_material

About 1/2way down, there's some details.
 
  • #3
Andy Resnick said:
If I understand what you are asking, the number of independent material constants reflect the amount of symmetry in the material.

Most generally, the stress-strain relationship is tensor in nature:
[tex] \boldsymbol{\sigma} = \mathsf{c}:\boldsymbol{\varepsilon}[/tex]

It's important to realize that the stress and strain terms themselves can be applied not only to mechanical behavior, but electrodynamic as well via, for example, the Maxwell stress tensor.

writing it out explicitly:

[tex] \sigma_{ij} = c_{ijk\ell}~ \varepsilon_{k\ell} [/tex]

For mechanics, given a material with *no* symmetry,the 9 stress components are related to the 9 strain components via a 81-component tensor.

Symmetry reduces the number of independent components of the 4th rank tensor.

http://en.wikipedia.org/wiki/Orthotropic_material

About 1/2way down, there's some details.

Thanks. I'm so confused I can't even formulate a decent question. Let me try again.

What I'm trying to understand is described in the Orthotropic material section of this link

http://www.engin.brown.edu/courses/En222/Notes/Constitutive/Constitutive.htm

How do I go from understanding E (in 3 directions) v(in three directions) G(in three directions) to C11, c22, c33, c12, c13, c23, c44,c55, c66? What's the basic idea of what's going on here?

Thanks,

John
 
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  • #4
I didn't see a 'G' on that page, but did you follow the linear elasticity section down to the "Matrix form of the constitutive relations" section? That shows how these tensors can be written more compactly. The section "Elastic Symmetries" explains why some of 'c' components are zero- is that the part you are having trouble with?
 
  • #5
Andy Resnick said:
I didn't see a 'G' on that page,...

I believe they use u (mu) for shear modulus. So:

c44 = u12 = G12
c55 = u13 = G13
c66 = u23 = G23

Is that right?

Is there a formula that allows one to calculate Gij from other properties?

.. but did you follow the linear elasticity section down to the "Matrix form of the constitutive relations" section? That shows how these tensors can be written more compactly. The section "Elastic Symmetries" explains why some of 'c' components are zero- is that the part you are having trouble with?

Well I started with more conceptional missunderstanding than that but at this point I get the idea of what's going on and why you want 9 constants and how the linear equations solve the stress/strain in all directions. So that's progress.

At this point I'm thinking I better go back and make sure I understand all of the basic relationships for isotopic materials. I mostly do but the releationships betwen E G and v are a bit fuzzy. But with some thought I think I can clear that up.

Then maybe I need a book to cover more details of the orthotopic material constants if I need to get that far into it. That is, why is that matrix set up the way it is, etc.

Even though my questions were fuzzy this exchange somehow helped me get over the major problem that I was having.

Thanks,

John
 

FAQ: Orthotropic materials defined by 9 constants

What are orthotropic materials?

Orthotropic materials are solid materials that have different mechanical properties in three mutually perpendicular directions. This means that they have unique strengths and stiffnesses in the x, y, and z axes, as opposed to isotropic materials which have the same properties in all directions.

How are orthotropic materials defined?

Orthotropic materials are defined by 9 constants, also known as the 9 elastic constants. These constants describe the material's strengths and stiffnesses in each of the three axes, as well as how the material responds to shear and thermal stresses.

What are the advantages of using orthotropic materials?

Orthotropic materials have several advantages over isotropic materials, including greater strength and stiffness in specific directions, higher resistance to deformation and warping, and the ability to tailor material properties to specific applications.

What are some examples of orthotropic materials?

Some common examples of orthotropic materials include wood, composite materials such as carbon fiber, and some types of metals like aluminum and titanium. Many biological materials, such as bones and plant fibers, are also orthotropic.

How are orthotropic materials used in engineering and design?

Orthotropic materials are commonly used in engineering and design applications where specific material properties are required in different directions, such as in aerospace and automotive industries. They are also used in structural components, such as bridges and buildings, where high strength and stiffness are necessary.

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