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benf.stokes
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Oscillation and Rotation
Question nr 1:
You have ruler of length L and thickness 2d resting, in equilibrium , on a cylindrical body of radius r. Slightly unbalancing the ruler, and existing attrition between the surfaces prove that the ruler has a oscillatory motion of period:
[tex] T = 2\cdot \pi\cdot \sqrt{\frac{L^2}{12\cdot g\cdot (r-d)}} [/tex]
Question nr 2:
Assuming the sphere roles down without sliding prove that the acceleration of it's center of mass is:
[tex] a= \frac{g\cdot \sin(\theta)}{1+\frac{2}{5}\cdot \frac{1}{1-\frac{1}{4}\cdot \alpha^2}}[/tex]
Where g is the gravitational acceleration and
[tex]\alpha= \frac{L}{R}[/tex]
Note: The moment of inertia of the sphere is:
[tex]I= \frac{2}{5}\cdot M\cdot R[/tex]
[tex]T=\frac{2\cdot \pi}{\omega}[/tex]
[tex]\tau= F\cdot r\cdot \sin(\varphi)[/tex]
At question nr 1 I can't wrap my mind about the idea that the ruler won't immediately begin to fall and in question nr 2 I get to:
[tex]a= \frac{g\cdot \sin(\theta)}{1+\frac{2}{5}\cdot \sqrt{\frac{1}{1-\frac{1}{4}\cdot \alpha^2}}}[/tex]
Homework Statement
Question nr 1:
You have ruler of length L and thickness 2d resting, in equilibrium , on a cylindrical body of radius r. Slightly unbalancing the ruler, and existing attrition between the surfaces prove that the ruler has a oscillatory motion of period:
[tex] T = 2\cdot \pi\cdot \sqrt{\frac{L^2}{12\cdot g\cdot (r-d)}} [/tex]
Question nr 2:
Assuming the sphere roles down without sliding prove that the acceleration of it's center of mass is:
[tex] a= \frac{g\cdot \sin(\theta)}{1+\frac{2}{5}\cdot \frac{1}{1-\frac{1}{4}\cdot \alpha^2}}[/tex]
Where g is the gravitational acceleration and
[tex]\alpha= \frac{L}{R}[/tex]
Note: The moment of inertia of the sphere is:
[tex]I= \frac{2}{5}\cdot M\cdot R[/tex]
Homework Equations
[tex]T=\frac{2\cdot \pi}{\omega}[/tex]
[tex]\tau= F\cdot r\cdot \sin(\varphi)[/tex]
The Attempt at a Solution
At question nr 1 I can't wrap my mind about the idea that the ruler won't immediately begin to fall and in question nr 2 I get to:
[tex]a= \frac{g\cdot \sin(\theta)}{1+\frac{2}{5}\cdot \sqrt{\frac{1}{1-\frac{1}{4}\cdot \alpha^2}}}[/tex]
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