I Outright understanding L/R inductor time constant

AI Thread Summary
The discussion centers on the behavior of an LR circuit when an external voltage is applied. It highlights that while a higher voltage increases the current more rapidly, it also results in a larger final current, leading to a balance that keeps the time constant independent of the voltage. The time constant, determined by the resistance (R) and inductance (L), indicates that a greater resistance results in a shorter charging time for the inductor. This relationship is supported by differential equations that describe the system's dynamics. Ultimately, the time required for the inductor to charge is influenced by resistance rather than the applied voltage.
abdulbadii
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Scientifically understanding L/R inductor time constant r reciprocates it
How is the real understanding, when an external constant E potential (voltage) is imposed/applied on a LR circuit, that is being charged as the characteristic L/R inductor time constant: the greater R the shorter time inductor get (full) charged

This absolutely independent to the E; it could simply be so great while time constant (charge time) still being shorter time than that of far less E, as proven or inspected by the (DE) equation
 
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abdulbadii said:
Summary: Scientifically understanding L/R inductor time constant r reciprocates it

as proven or inspected by the (DE) equation
yes.
 
A larger voltage means that the current increases faster, but it also means that the final current is larger. The two effects balance out so the time required is independent of the voltage.
 

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