Overimposed movement with friction

In summary, the problem involves describing the movement of a glider during tow, with a constant speed and cable length. The glider's area, lift and drag coefficients, and frictional coefficients of the tow line are known as a function of tangential speed. The starting line angle and nonconservative force are also given. The goal is to find an expression for Vt and/or alpha in terms of these parameters and other equations involving lift and drag forces.
  • #1
Akrobit
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Homework Statement


I need to describe a glider movement during tow. The tow is based on a single axis displacement (x) with constant speed Ps=5 m/s. The cable length is constant=50 m.. The glider area A, lift and drag coefficients (Cl and Cd) are known as a function of tangential speed (Vt).
The frictional coefficients of the tow line (Cdline) can be known as a function of local velocity. The diameter of the line is known=Ldiam. Y axis is vertical and the problem can be considered to develop only on the X-Y plane. The starting line angle (alpha) respect to x-axis of the movement can be about 20º. The nonconservative force (Px) pulling the tow line along the x-axis is the only external input energy.
Vt= tangential speed of glider
d=density of air
Ar=aspect ratio of glider wing
Cd0=coefficient rapresentative of other glider drag components proportional to square tangential velocity
Vlocal is the cvelocity of a certaion point of the tow line
The goal is to obtain an expresion for Vt and(or) alpha as a function of the other parameters



Homework Equations


Lift of the glider L=Cl(Vt)*d/2*Vt^2*A
Drag of the glider D=(Cd(Vt)+Cl(Vt)^2/pi/Ar+Cd0)*d/2*Vt^2*A
Drag coefficient for the line Cdline:3/log10(Reline)
Reline=65535*Ldiam*Vlocal




The Attempt at a Solution

 
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  • #2
I have tried to obtain the expressions for Vt and alpha, but it is not easy because of all the parameters involved. I have been able to find some equations that describe the motion of the glider in terms of the lift and drag forces, but I am not sure if they are correct. I think I need to use Newton's second law of motion to solve this problem, but I am not sure how to go about it.
 
  • #3


To describe the glider movement during tow, we must consider the forces acting on the glider and the tow line. The glider experiences a lift force and a drag force due to its motion through the air. The lift force is dependent on the glider's area, lift coefficient, and tangential speed, while the drag force is dependent on the glider's area, lift and drag coefficients, and the square of the tangential speed. In addition, there may be other drag components present, represented by the coefficient Cd0, which also contribute to the overall drag force experienced by the glider.

The tow line also experiences a drag force, which is dependent on its diameter, density of air, and local velocity. This drag force can be calculated using the drag coefficient for the line, which is a function of the Reynolds number of the tow line. The Reynolds number, in turn, is dependent on the tow line's diameter, density of air, and local velocity.

The goal of this problem is to obtain an expression for the tangential speed (Vt) and/or the starting line angle (alpha) as a function of the other parameters. To do this, we can use the equations for lift and drag, along with the known values for the glider's area, lift and drag coefficients, and the tow line's diameter and density of air. We can also use the equation for the drag coefficient of the line, substituting in the known values for the tow line's diameter and density of air, and solving for the local velocity.

Once we have an expression for the local velocity, we can substitute it into the equations for lift and drag to obtain expressions for the lift and drag forces on the glider. Finally, we can use these expressions, along with the known value for the external input energy (Px), to solve for the tangential speed and starting line angle. This will give us a complete understanding of the glider's movement during tow, taking into account the effects of friction on the tow line.
 

Related to Overimposed movement with friction

1. What is overimposed movement with friction?

Overimposed movement with friction is a type of motion where an object moves along a surface while experiencing frictional forces. This type of movement is common in everyday situations, such as when a car drives on a road or when a person walks on the ground.

2. How does friction affect overimposed movement?

Friction plays a crucial role in overimposed movement. It acts as a resistance force that opposes the motion of the object. This means that the object will require more force to overcome the friction and continue moving. Friction can also cause the object to slow down or come to a stop if the force applied is not enough to overcome it.

3. What factors affect the amount of friction in overimposed movement?

The amount of friction in overimposed movement depends on several factors, including the type of surface, the roughness of the surface, and the weight of the object. The rougher the surface, the higher the friction, and the heavier the object, the more force is needed to overcome the friction.

4. How can friction be reduced in overimposed movement?

There are several ways to reduce friction in overimposed movement. One way is to use lubricants, such as oil or grease, to reduce the contact between the surfaces. Another way is to use smoother surfaces or materials with lower coefficients of friction. Additionally, reducing the weight of the object can also help reduce friction.

5. How is overimposed movement with friction relevant in real-world applications?

Overimposed movement with friction is relevant in many real-world applications, such as transportation, sports, and manufacturing. Understanding friction and its effects on overimposed movement allows us to design more efficient transportation systems, improve athletic performance, and optimize machinery and equipment for various industries.

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