- #1
markosheehan
- 136
- 0
By using oxidation numbers can someone show me what is oxidised and reduced
Fe203+3co->2Fe+3co2
Fe203+3co->2Fe+3co2
markosheehan said:By using oxidation numbers can someone show me what is oxidised and reduced
Fe203+3co->2Fe+3co2
I like Serena said:Hi Marko,
Making the ion forms explicit, we have:
$$
{Fe^{3+}}_2{0^{2-}}_3+3C^{2+}O^{2-}\to 2Fe+3C^{4+}{O^{2-}}_2
$$
So $Fe$ gains electrons and as such it is reduced.
And $C$ loses electrons, meaning it is oxidized.
markosheehan said:thanks
I usually go to the periodic table and look at the elements valency and then i take this as the oxidation number. this is not always correct though?
for example carbon has a valency of 4 but in the above equation it is 2+.
so you go off the ones you know like oxygen is always -2 and the oxidation number of a compound must always equal zero.
The oxidation state of Fe in Fe2O3 is +3.
Fe2O3 reacts with CO in a redox reaction where Fe2O3 is reduced to Fe and CO is oxidized to CO2.
The overall change in oxidation numbers in the reaction is 0, as the Fe in Fe2O3 has an oxidation state of +3 and in Fe it is also +3, while the CO in CO is +2 and in CO2 it is +4.
Fe2O3 is a reducing agent in this reaction, as it causes the reduction of CO to CO2.
The oxidation state of Fe is determined by counting the number of electrons that are either gained or lost by Fe in the reaction. In this case, Fe is reduced from +3 to 0, meaning it has gained 3 electrons, making its oxidation state +3.