Parallel combination of capacitors

In summary: This should help you track how the charges are redistributed when the capacitors are reconnected in parallel. In summary, the problem involves two capacitors initially connected in parallel with opposite polarity plates together. The net charge after the combination is q1-q2 and the final potential is (C1V1-C2V2)/(C1+C2). A diagram can be drawn to track the redistribution of charges and explain how the same potential is maintained and charge is conserved. Further clarification is needed for a complete solution.
  • #1
Saint xavier
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0

Homework Statement


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If the 2 charged capacitors are reconnected in parallel with plates of opposite polarity together then ? is common potential. In this condition how charge is conserved and same potential is maintained

Homework Equations


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Net charge Q=C1V1-C2V2 Where C1V1=q1 and C2v2=q2
V = (C1V1-C2V2)/(C1+C2) Where C1 and V1 are capacitance and potential of one and C2 and V2 are of other?

The Attempt at a Solution


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I solved but got confused in how they will attain same potential with charge conservation. Initially in a system net charge was q1+q2 but after combination it was q1-q2. Please describe the soln with description for charge conservation and common potential.
 
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  • #2
Hi Saint xavier, Welcome to Physics Forums!

Saint xavier said:

Homework Statement


[/B]
If the 2 charged capacitors are reconnected in parallel with plates of opposite polarity together then ? is common potential. In this condition how charge is conserved and same potential is maintained

Homework Equations


[/B]
Net charge Q=C1V1-C2V2 Where C1V1=q1 and C2v2=q2
V = (C1V1-C2V2)/(C1+C2) Where C1 and V1 are capacitance and potential of one and C2 and V2 are of other?

The Attempt at a Solution


[/B]
I solved but got confused in how they will attain same potential with charge conservation. Initially in a system net charge was q1+q2 but after combination it was q1-q2. Please describe the soln with description for charge conservation and common potential.
Your problem statement seems to be incomplete. It's not clear how the capacitors were initially connected or to what potential difference(s) they were charged. Can you clarify this by providing the complete problem statement?

Try drawing a diagram for each connection scenario and label each capacitor plate with the charge it holds.
 

FAQ: Parallel combination of capacitors

1. What is a parallel combination of capacitors?

A parallel combination of capacitors refers to a circuit configuration where multiple capacitors are connected side by side, with each one having a common positive and negative terminal. This allows the capacitors to share the same voltage across them, while the total capacitance of the circuit is equal to the sum of the individual capacitances.

2. How does the total capacitance change in a parallel combination?

In a parallel combination, the total capacitance is equal to the sum of the individual capacitances. This means that if two capacitors with capacitance values of C1 and C2 are connected in parallel, the total capacitance would be C1 + C2. The total capacitance increases as more capacitors are added in parallel.

3. What is the effect of a parallel combination on the overall capacitance of a circuit?

A parallel combination of capacitors increases the overall capacitance of a circuit. This is because the capacitors in parallel share the same voltage, resulting in a larger total charge that can be stored in the circuit.

4. How does parallel combination affect the equivalent resistance of a circuit?

In a parallel combination, the equivalent resistance decreases as more capacitors are added. This is because the individual resistances of the capacitors decrease when they are connected in parallel, allowing more current to flow through the circuit.

5. Is there a limit to the number of capacitors that can be connected in parallel?

There is no limit to the number of capacitors that can be connected in parallel. However, as more capacitors are added, the overall capacitance of the circuit will approach a maximum value. This is due to the diminishing returns of adding more capacitors in parallel, as the increase in capacitance becomes less significant with each additional capacitor.

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