Parallel Plate Capacitor Diameter

In summary, two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 1.70 ×109 electrons from one disk to the other results in an electric field strength of 3.50 ×105N/C between the disks. To find the diameters of the disks, we can use the formula for parallel plate capacitors and convert the given charge to Coulombs. Then, we can use Gauss's law to obtain the area and find the diameter of the disks.
  • #1
tomizzo
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Homework Statement



Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 1.70 ×109 electrons from one disk to the other causes the electric field strength to be 3.50 ×105N/C.

What are the diameters of the disks?

Homework Equations



Refer to attachment

The Attempt at a Solution



So I substitute everything into the formula and end up getting R = .5 mm. I then double this to find the diameter and still get the wrong answer. Any ideas?
 

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  • #2
tomizzo said:

Homework Statement



Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 1.70 ×109 electrons from one disk to the other causes the electric field strength to be 3.50 ×105N/C.

What are the diameters of the disks?

Homework Equations



Refer to attachment

The Attempt at a Solution



So I substitute everything into the formula and end up getting R = .5 mm. I then double this to find the diameter and still get the wrong answer. Any ideas?

Not sure what you're intending to do with that equation you attached. It looks like the on-axis field for a charged circular disk at some distance z from the disk along the axis. But here you have a parallel plate capacitor and the field will be (essentially) uniform between the parallel plates.

Look instead to formulas related to parallel plate capacitors.
 
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  • #3
convert Q to Coulombs, then use Gauss to obtain Area.
 

Related to Parallel Plate Capacitor Diameter

1. What is a parallel plate capacitor diameter?

A parallel plate capacitor diameter refers to the distance between the two conducting plates in a capacitor that are parallel to each other. It is one of the key factors that determine the capacitance of a capacitor.

2. How is the diameter of a parallel plate capacitor calculated?

The diameter of a parallel plate capacitor can be calculated by using the formula d = (2*A/C)^1/2, where d is the diameter, A is the area of the plates, and C is the capacitance.

3. How does the diameter of a parallel plate capacitor affect its capacitance?

The diameter of a parallel plate capacitor directly affects its capacitance. The larger the diameter, the larger the surface area of the plates, which results in a higher capacitance. This is because a larger surface area allows for more charge to be stored between the plates.

4. Can the diameter of a parallel plate capacitor be changed?

Yes, the diameter of a parallel plate capacitor can be changed by altering the distance between the two plates. This can be done by moving the plates closer together or farther apart, which will in turn affect the capacitance of the capacitor.

5. What are some real-world applications of parallel plate capacitors with different diameters?

Parallel plate capacitors with different diameters have various applications in electronics and technology. They are commonly used in power supplies, filters, and signal amplifiers. They are also used in touch screens, sensors, and as energy storage devices in hybrid and electric vehicles.

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