- #1
Dayna
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Two parallel metal plates are separated by 1.5 cm and are maintained at a potential difference of 1200 V. A proton, initially at rest, is released from the poisitive plate. When it reaches the negative plate its speed is :
So i know that potential energy is Vq.
So i went 1200 V x 1.602 x 10-19, but I have no idea where to go from there.
Thanks!
So i know that potential energy is Vq.
So i went 1200 V x 1.602 x 10-19, but I have no idea where to go from there.
Thanks!