Parallel RLC Circuits - Help please

In summary, the question asks for an equation to find the impedance of a L-RC circuit at resonance. The resonance frequency is given, and the Q factor too. You also know the voltage and current at resonance. From these, you can calculate the approximate values of L, R, C.
  • #1
edd83
3
0

Homework Statement



I'm working through this question, but on the final part I've hit a brick wall so I'd be grateful for any help please.

The tuned circuit has a Q-factor of 1000 and is designed to resonate at 1MHz. At resonance, the supply current I is measured at 15μA for supply voltage of 2.5V. The load resistor, RL is 10k ohms. The part of the question I'm not getting is:

Estimate the impedance offered to the supply at resonance and at the frequencies of + and - 2% from resonance

Homework Equations



I have also found that the bandwidth is 1kHz, at resonance the value of L is 25.33μH and the value of R is 0.162 ohms

The Attempt at a Solution



Could anyone suggest an equation? I'm stumped and can't think of what I need.
 

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  • #2
Try calculating your complex impedance with the standard impedance equations for an inductor, resistor, and capacitor at the resonance frequency given. After finding the complex impedance in rectangular form, convert it to polar form and remember that current division still applies even when in the phasor realm.

For the +/- 2% part, just add and subtract 2% of your resonance frequency and recalculate.
 
  • #3
Hi Relleck, thank you for your reply, I'll give that a try.

Forgive me for missing the bottom of the question off, is says 'use a 'narrow-band' approximation to find the impedance of the L-RC circuit'. Any idea what one of these is??
 
  • #4
edd83 said:
Hi Relleck, thank you for your reply, I'll give that a try.

Forgive me for missing the bottom of the question off, is says 'use a 'narrow-band' approximation to find the impedance of the L-RC circuit'. Any idea what one of these is??

I think it means that you can approximate the resonant angular frequency at ω0≈1/√(LC), and Q≈(ω0L)/R

ehild
 
  • #5
Hi ehild, forgive me, how would I then go about finding the impedance?
 
  • #6
The resonance frequency is given, and the Q factor too. You also know the voltage and current at resonance. From these, you can calculate the approximate values of L, R, C. You need the impedance of the whole circuit (between the terminals of the supply).ehild
 

FAQ: Parallel RLC Circuits - Help please

1. What is a parallel RLC circuit?

A parallel RLC circuit is a type of electrical circuit that contains a resistor (R), an inductor (L), and a capacitor (C) connected in parallel. This means that the voltage across each component is the same, while the current through each component may differ.

2. How does a parallel RLC circuit differ from a series RLC circuit?

A series RLC circuit has all three components connected in a series, which means that the same current flows through each component. In contrast, a parallel RLC circuit has each component connected in parallel, meaning that the voltage across each component is the same, while the current through each component may differ.

3. What is the resonance frequency of a parallel RLC circuit?

The resonance frequency of a parallel RLC circuit is the frequency at which the impedance of the circuit is at its minimum. This occurs when the reactance of the inductor and the capacitor cancel each other out, resulting in a purely resistive circuit. The resonance frequency can be calculated using the formula fr = 1/(2π√(LC)).

4. How do I calculate the total impedance of a parallel RLC circuit?

The total impedance of a parallel RLC circuit can be calculated using the formula ZT = √((R2 + (XL − XC)2)), where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.

5. What is the purpose of a parallel RLC circuit?

A parallel RLC circuit is used for a variety of applications, including filtering, tuning, and impedance matching. It is also used in electronic devices such as radios and amplifiers to control the flow of electricity and tune to specific frequencies.

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