Parametric Equation Homework: Show Constant of ##\frac{d^2y}{dx^2}/(dy/dx)^4##

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The discussion focuses on proving that the expression ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant for the given parametric equations ##x=t^3+1## and ##y=t^2+1##. Participants explain the process of differentiating both equations with respect to ##t## and applying the chain rule to derive ##\frac{dy}{dx}## and subsequently ##\frac{d^2y}{dx^2}##. The calculation leads to ##\frac{d^2y}{dx^2}=\frac{1}{3t}##, which is substituted back into the original expression. The discussion emphasizes the importance of using the chain rule correctly in the differentiation process. The conclusion confirms that the derived expression is indeed a constant.
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Homework Statement


A curve is defined by the parametric equations ##x=t^3+1## and ##y=t^2+1##.
Show that ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant.

Homework Equations

The Attempt at a Solution


So you differentiate both equations wrt ##t## then apply the chain rule to get ##\frac{2}{3t}##. Applying the chain rule after differenating twice to get ##\frac{d^2y}{dx^2}=\frac{1}{3t}##.
Substitute in both to get the result?
 
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squenshl said:

Homework Statement


A curve is defined by the parametric equations ##x=t^3+1## and ##y=t^2+1##.
Show that ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant.

Homework Equations

The Attempt at a Solution


So you differentiate both equations wrt ##t## then apply the chain rule to get ##\frac{2}{3t}##. Applying the chain rule after differenating twice to get ##\frac{d^2y}{dx^2}=\frac{1}{3t}##.
Substitute in both to get the result?
Yes. Keep in mind that ##\frac{d^2 y}{dx^2} = \frac d {dx} \left(\frac {dy}{dx}\right) \cdot \frac {dt}{dx}##, using the chain rule.
 
Mark44 said:
Yes. Keep in mind that ##\frac{d^2 y}{dx^2} = \frac d {dx} \left(\frac {dy}{dx}\right) \cdot \frac {dt}{dx}##, using the chain rule.
Got it thanks a lot
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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