Particle collides totally inelastically with a vertical free rod

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In a totally inelastic collision, a particle of mass M collides with a vertical rod of the same mass, resulting in a combined system that rotates about its center of mass. The conservation of momentum and angular momentum principles are crucial for solving the problem. The center-of-mass velocity can be determined using these conservation laws, while the moment of inertia is calculated based on the combined masses and geometry. The angular speed of the system post-collision is derived from the moment of inertia and the linear velocity. Understanding the rotation point as the center of mass is essential for accurate calculations.
rbwang1225
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Homework Statement


A particle of mass M moving on a frictionless surface with velocity ##V_0## collides totally inelastically with an uniform vertical rod of mass M and length L. After immediately the collision, what is the center-of-mass velocity, the moment of inertia about the center-of-mass, and the angular speed of the system.

Homework Equations


conservation of momentum and conservation of angular momentum
moment of inertia

The Attempt at a Solution


I am wondering what point does the particle+rod system will rotate about?
 
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First form the two equations. Conservation of linear and Conservation of angular momentum. As there is no external force and Torque.
 
rbwang1225 said:

The Attempt at a Solution


I am wondering what point does the particle+rod system will rotate about?
The problem statement mentions "the moment of inertia about the center-of-mass", so that is a pretty good clue.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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