- #1
Katie1990
- 6
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Homework Statement
A particle of mass M, traveling horizontally through the laboratory, decays into two daughter
particles, each of mass 0.4M. One of the daughters, A, is produced at rest in the Lab frame.
Show that vcm , the speed with which the CM frame moves in the Lab frame, is equal to
0.6c, and find the energy of the parent particle in the Lab frame.
Homework Equations
Conservation of 4-momentum, Relativistic energy momentum relation
The Attempt at a Solution
I have found the energys and velocities of the two daughter particles in the com frame, but am unsure how to show that Vcm is equal to 0.6c. I tried finding the energy by writing the momentum of the the stationary daughter as p1 = P - p2 and finding the square of that then rearranging to get energy but this didn't work.