Particle in a box in momentum basis

[Ravi Mohan]

I will have to think and work it out. But essentially, as you say, the vectors in the domain of $\hat{P}^\dagger$ and $\hat{P}$ need not satisfy any extra boundary condition (save square integrability and vanishing at infinity), their domain should turn out same.

 

[Joker93]

I will have to think and work it out. But essentially, as you say, the vectors in the domain of $\hat{P}^\dagger$ and $\hat{P}$ need not satisfy any extra boundary condition (save square integrability and vanishing at infinity), their domain should turn out same.

Great, I think I got it! Thanks!
Also, your blog is excellent!

 

[Joker93]

If anybody could help me, I asked a question that is connected to this one:
https://www.physicsforums.com/threa...r-the-free-particle-position-operator.880324/