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Peppino
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Can someone please check that everything I have done so far is correct?
A particle movies along a parabola with the displacement equation s = 0.5t2.
(a graph is shown)
::::Part I::::
Suppose x-component is s = Ct
i) indicate direction of velocity vector and acceleration at point R (arbitrary point on graph)
ii) Determine y-component of particles velocity
iii) Determine y-component of particles acceleration
Answers:
i) I suppose the velocity vector would be tangential to the graph and the acceleration vector would be parallel with the y-axis?
ii) since V = √(Vx2 + Vy2), and V = t, I found that the y - component is √(t2-C2t2).
iii) Since the acceleration is constant, is the y-component simply C?
:::Part II::::
Suppose instead that the x-component of the velocity is given by [tex]\frac{C}{\sqrt{1 + t^{2}}}[/tex]
i) Show that the particle's speed is constant
I am unsure how to attempt Part II.
If you are able to answer or confirm my answers to any part of this question, thank you very much!
A particle movies along a parabola with the displacement equation s = 0.5t2.
(a graph is shown)
::::Part I::::
Suppose x-component is s = Ct
i) indicate direction of velocity vector and acceleration at point R (arbitrary point on graph)
ii) Determine y-component of particles velocity
iii) Determine y-component of particles acceleration
Answers:
i) I suppose the velocity vector would be tangential to the graph and the acceleration vector would be parallel with the y-axis?
ii) since V = √(Vx2 + Vy2), and V = t, I found that the y - component is √(t2-C2t2).
iii) Since the acceleration is constant, is the y-component simply C?
:::Part II::::
Suppose instead that the x-component of the velocity is given by [tex]\frac{C}{\sqrt{1 + t^{2}}}[/tex]
i) Show that the particle's speed is constant
I am unsure how to attempt Part II.
If you are able to answer or confirm my answers to any part of this question, thank you very much!
Last edited: