- #1
J-dizzal
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Homework Statement
A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.30 s, it is at point (5.10 m, 6.80 m) with velocity (3.90 m/s) ## \hat j ##and acceleration in the positive x direction. At time t2 = 9.90 s, it has velocity (–3.90 m/s) ## \hat i ##and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.
Homework Equations
a=v2/r
The Attempt at a Solution
im having trouble getting started on this one. if only drawn a diagram with the particles plotted along the orbit and their tangential velocity vectors
the point at t=3.30s is on the very left of the orbit and the point at t=9.90s is on the very bottom of the orbit.
the center point of the circle is in quadrant 1
https://www.dropbox.com/s/x36hlpj0btsrl9u/20150622_205717.jpg?dl=0
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