Particles under constant acceleration

In summary, a driver slams on the brakes when he sees a tree blocking the road, causing the car to slow down with an acceleration of -5.60 m/s^2 for 4.20s. This results in straight skid marks 62.4m long ending at the tree. To find the speed at which the car hits the tree, the equation Vf=Vi+at is used. However, the initial velocity (Vi) must be found first. Using the equation xf=xi+Vxit+1/2at^2 and the given values, Vi is calculated to be 26.6 m/s. Then, using the equation Vavg=Vi+Vf/2, the final velocity
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Homework Statement



Okay, wordy. Read through though, please :smile:

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with an acceleration of -5.60 m/s^2 for 4.20s, making straight skid marks 62.4m long ending at the tree. At what speed does it hit the tree?

Homework Equations



Vf=Vi+at

The Attempt at a Solution



So I saw I had a=-5.60m/s^2, t=4.20s, xf=62.4m, and Vf=0 (since after he hit the tree, he stopped).

So I plugged them into Vf=Vi+at (or rather Vi=Vf-at), or 0-(-5.60)*4.20, to give 23.52 m/s. It seems wrong, though. Suggestions or advice?
 
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  • #2
you jumped ahead by setting Vf to 0, you simply want to solve for Vf to find out what speed it is going when it hits the tree (as the question asks).

they also give you a time and distance, so you have an average velocity to help figure out the initial velocity in terms of the final velocity (or vice versa)After it hits the tree, it experiences another negative acceleration as it crumples against the tree, each piece of the car at different rates; but that would be a different problem all together.
 
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  • #3
Oh...so I'm to find the average velocity, right? Umm...that's x/t, which is 62.4/4.20, which gives 14.9.

Then, I would have to find the initial velocity, uh huh? xf=xi+Vxit+1/2at^2...Vi=26.6.

Then Vavg=Vi+Vf/2 would come to play...14.9=26.6+x/2, gives a different answer, Vf=3.10m/s. It looks a little bit more correct, so thanks.
 

FAQ: Particles under constant acceleration

What is constant acceleration?

Constant acceleration refers to the steady change in an object's velocity over time. This means that the object's speed increases or decreases by the same amount in each unit of time. It is often represented by the symbol "a" and measured in meters per second squared (m/s²).

How is constant acceleration calculated?

The formula for calculating constant acceleration is a = (vf - vi) / t, where "a" is the acceleration, "vf" is the final velocity, "vi" is the initial velocity, and "t" is the time interval. This formula can be used to find any of the three variables as long as the other two are known.

What is the difference between constant acceleration and uniform acceleration?

Constant acceleration and uniform acceleration are often used interchangeably, but there is a slight difference. Constant acceleration refers to a steady change in velocity, while uniform acceleration specifically refers to an object moving in a straight line with a constant acceleration.

What is the relationship between constant acceleration and force?

According to Newton's second law of motion, force is directly proportional to acceleration. This means that the greater the force applied to an object, the greater its acceleration will be. In other words, a constant force will result in a constant acceleration.

How does air resistance affect particles under constant acceleration?

Air resistance, also known as drag force, can affect particles under constant acceleration by slowing them down. This is because as an object moves through the air, the air molecules exert a force on the object in the opposite direction of its motion. This can cause a decrease in the object's acceleration, as well as a decrease in its velocity over time.

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