- #1
mathmari
Gold Member
MHB
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Hey!
Suppose we have a non-homogeneous differential equation $Ly=f$ in the ring of exponential sums $\mathbb{C}[e^{\lambda x} \mid \lambda \in \mathbb{C}]$, then $f=\alpha_ie^{b_i x}$, right?
When $b_i$ is a root of the characteristic equation of the homogeneous equation of multiplicity $M$, then how is the particular solution?
Is it $$y(x)=Cx^Me^{b_i x}$$ or $$y(x)=e^{b_i x} (A_0+A_1x+ \dots +A_{M}x^{M})$$ ? (Wondering)
Suppose we have a non-homogeneous differential equation $Ly=f$ in the ring of exponential sums $\mathbb{C}[e^{\lambda x} \mid \lambda \in \mathbb{C}]$, then $f=\alpha_ie^{b_i x}$, right?
When $b_i$ is a root of the characteristic equation of the homogeneous equation of multiplicity $M$, then how is the particular solution?
Is it $$y(x)=Cx^Me^{b_i x}$$ or $$y(x)=e^{b_i x} (A_0+A_1x+ \dots +A_{M}x^{M})$$ ? (Wondering)
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