- #1
Silversonic
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Homework Statement
It's not a homework question. It's a piece of my textbook I don't understand.
Here's what it says
In a two electron atom, taking the orbital states of two electrons to be the same, then the antisymmetric wavefunction tends to zero, as well as the quantum numbers n, l and m(l) are the same for the electrons. Therefore, the possible spin wavefunctions are;
[itex]\chi[/itex][itex]_{a}[/itex], S = 0 (m[itex]_{s}[/itex] = 1/2 for one electron and m[itex]_{s}[/itex] = -1/2 for the other.[itex]\chi[/itex][itex]_{s}[/itex], S = 1 (electrons have the same (parallel) spin, i.e. both m[itex]_{s}[/itex] = 1/2 or -1/2), Since this combines with the antisymmetric orbital wavefunction which is zero, the total combined wavefunction of the orbital does not exist.
So we must have that an electron cannot exist with all the same four quantum numbers.
What I don't under is the bolded bit. It says that for S = 1 the electrons have the same spin. But surely this is untrue, it's possible to have m[itex]_{s}[/itex] = 1/2 for one electron and m[itex]_{s}[/itex] = -1/2 for another, but S = 1 still, as shown by this diagram;
http://img21.imageshack.us/img21/4033/12986325.png
i.e the M[itex]_{s}[/itex] = 0 in the middle (capitalised M) gives a state with S = 1 but m[itex]_{s}[/itex] = 1/2 for one and -1/2 for the other. Admittedly it doesn't matter since it combines with a 0 antisymmetric wavefunction, but still.
This same concept that I don't understand is used in the description of orthohelium. I'm not sure if orthohelium is defined as a helium atom where two electrons have the same spin, because as far as I see and anti-symmetric orbital wavefunction paired with a symmetric spin wavefunction (S=1) (which is orthohelium's wavefunction) can have electrons with different m[itex]_{s}[/itex].
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