- #1
tdog13
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Homework Statement
Converting the simple pendulum expression for g in terms of the angular frequency ω instead of the period T, where ω=2π/T, yields g=ω2L.
Derive an expression for the error (Δg) in g by first setting g=A⋅B.
A=
B=
Therefore in terms of A, ΔA, B, and ΔB:
Δg/g=
Converting back to the original variables ω and L:
ΔA/A=
ΔB/B
Thus, an expression for the error Δg in g is:
Δg=
Homework Equations
The simple pendulum expression I have is T = 2pi √(L/g)
The Attempt at a Solution
I am in my first year physics class. Already on the first week the professor requires questions like this to be completed prior to my lab. The problem is... we haven't learned ANYTHING yet in class that is relevant to this question. I am not sure where to even begin, I am having difficulty comprehending and picturing what the question is asking. It would be great if anyone can provide any insight or lead me in the correct path