- #1
soccerdude010
- 1
- 0
Percent Uncertainty Problem -NEED URGENT HELP!
The question is: What, approximately, is the percent uncertainty for the measurement given as 1.57 m^2.
I know the formula that this textbook: 6th edition: Physics - Giancoli gave. It is simply, the ratio of the uncertainty to the measured value, multiplied by 100.
I have tried numerous attempts and for some reason, I couldn't seem to come up with the right answer the book gives in the back. I'm really not sure what other way to do it.
I tried, simply to put:
(.01)/1.57 * 100 = .64%
(.01)/(1.57^2) * 100 = .41%
(1.58-1.57)/1.57 *100 = .64%
...the correct answer in the back of the book is 1%. I kept using .01 because the measured value they gave me 1.57m^2. I am not sure whether I messed up there, I was hoping someone could help me. Thanks
Homework Statement
The question is: What, approximately, is the percent uncertainty for the measurement given as 1.57 m^2.
Homework Equations
I know the formula that this textbook: 6th edition: Physics - Giancoli gave. It is simply, the ratio of the uncertainty to the measured value, multiplied by 100.
The Attempt at a Solution
I have tried numerous attempts and for some reason, I couldn't seem to come up with the right answer the book gives in the back. I'm really not sure what other way to do it.
I tried, simply to put:
(.01)/1.57 * 100 = .64%
(.01)/(1.57^2) * 100 = .41%
(1.58-1.57)/1.57 *100 = .64%
...the correct answer in the back of the book is 1%. I kept using .01 because the measured value they gave me 1.57m^2. I am not sure whether I messed up there, I was hoping someone could help me. Thanks
Last edited: