- #1
mrcotton
- 120
- 0
Homework Statement
If a diameter of 15.5 +/- 0.1mm has been quoted and you need to turn this to a percentage error
you get (0.1/15.5)*100 = 0.645...
so you would quote this as a percentage error of 0.6%
If it was 15.3 +/- 0.1mm and again you wanted percentage error
(0.1/15.3)*100 = 0.653...
So you would quote as 0.7%
So this is not to do with significant figures but the decimal place in which the uncertainty manifests?
I would be grateful if someone could tell me if this logic is correct
Thanks