- #1
Stellaferox
- 16
- 0
Hi,
I have this problem in which a word (lets say "ABERRATIONAL") is given. Now how many permutations (no unique words) can be made given that the 3 A's have to be next to each other?
My solution: regard the 3 A's as one block, so we have 12-3+1 = 10 letters. This gives 10! permutations. The 3 A's yield 3! permutations. Answer = 10!.3!
This is wrong. The answer should be 302.400.
Help and insight is appreciated!
regards,
Marc
I have this problem in which a word (lets say "ABERRATIONAL") is given. Now how many permutations (no unique words) can be made given that the 3 A's have to be next to each other?
My solution: regard the 3 A's as one block, so we have 12-3+1 = 10 letters. This gives 10! permutations. The 3 A's yield 3! permutations. Answer = 10!.3!
This is wrong. The answer should be 302.400.
Help and insight is appreciated!
regards,
Marc