Permutations and Combinations of the word POSSESSES

In summary, the problem involves selecting and arranging letters from the word POSSESSES. When the letters are repeated, the formula for combinations and arrangements cannot be applied directly. Instead, one can use casework to find the possible arrangements for different cases based on the repetitions of letters.
  • #1
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Homework Statement


The letters of the word POSSESSES are written on 9 cards, one on each card. The cards are shuffled and four of them are selected and arranged in a straight line.

Homework Equations



(a) how many possible selections are there of 4 letters?
(b"how many arrangements are there of 4 letters?


The Attempt at a Solution



Well first of all, how do you start of a question like this. for the first part(a)
9C4=126 but here i see there are 5 s's and 2 e's. how can i apply the formula to this question. because there are 5 s's and 2e's so this forumla is invalid.

for arrangements for 9 words. 9!/5!2! but this is for the 9 letters. i am only focusing on the four words being selected. how can i start
 
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  • #2
the problem here is that all the letters are not different. there are two e's and 5s's how do you approach the question when the letters are repeated.
 
  • #3
I do not know a simple way of doing this, but there is little enough that you can crunch through it with casework. Separate cases based on repetitions of letters. For example, one case would be the possible arrangements with 4 S's. Another could be the possible arrangements with 2 S's and 2 E's, etc.
 

FAQ: Permutations and Combinations of the word POSSESSES

How many different arrangements of the letters in the word POSSESSES are possible?

There are 9 letters in the word POSSESSES, so there are 9 factorial (9!) possible arrangements, which is equal to 362,880.

What is the difference between a permutation and a combination?

A permutation is an arrangement of a set of items in a specific order, while a combination is a selection of items from a set without regard to order.

How many ways can the word POSSESSES be arranged if the first and last letter must always be an S?

If the first and last letter must always be an S, then there are 7 remaining letters to arrange. This can be done in 7 factorial (7!) ways, which is equal to 5,040.

How many arrangements of the word POSSESSES have the letters P and S next to each other?

To have the letters P and S next to each other, we can treat them as one letter. So we have 8 letters to arrange (PS, O, S, S, E, S, S, E), which can be done in 8 factorial (8!) ways, or 40,320.

In how many ways can the letters in the word POSSESSES be arranged if the two S's must be together?

If the two S's must be together, we can treat them as one letter, so we have 8 letters to arrange (PO, SS, E, S, E, S, E), which can be done in 8 factorial (8!) ways, or 40,320.

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