- #1
DodgeViperEvilTwin
- 8
- 0
So I have been trying to derive peukerts exponent based on assumptions I know this won't be accurate but I am curious about the data. So I don't know the time to discharge the battery so I guessed 3 Hours the capacity at a 20 hour rate is 40Ah meaning the manufacturer rated discharge current was 2A. However I ran into an issue with this because I get log(3)=log((40/(2*20))^k) then when I take log base 2 of 1 I get 0. Mathematically I see this but I am not sure why trying to find for k this way won't work. I know assuming some random discharge time makes no sense but let's say experimentally I found that to be 3 when using a discharge current of 2A then could I use the equation in this way? I still could not because I would still get a 0 on the other side. So I guess my question actually is why can't I use this equation in the manner I am trying? It must be because they are inherrrent losses in the battery and so the capacity listed in the numerator won't be exactly as rated.