Why does the pH of a diluted solution change?

  • Thread starter Bohrok
  • Start date
  • Tags
    Ph
In summary, the pH does change since H3O+ changes, which is why using the Henderson-Hasselbalch equation equation both before and after dilution would give the same pH.
  • #1
Bohrok
867
0
The first time I came across a chemistry problem about the pH of a solution that's been diluted, I thought there was an argument for a change and for no change. After doing some searching online, it seems that the pH does change since [H3O+] changes, which I understand. However, using the Henderson–Hasselbalch equation equation both before and after dilution would give the same pH, right?

As an example, if I have x moles each of HA and A- in 1 L solution, then[tex]pH = pK_a + \log\left(\frac{\frac{x\text{ mol }A^-}{1 L}}{\frac{x\text{ mol }HA}{1 L}}\right) = pK_a + \log(1) = pK_a[/tex]Now if the solution were at 2 L to start with, then[tex]pH = pK_a + \log\left(\frac{\frac{x\text{ mol }A^-}{2 L}}{\frac{x\text{ mol }HA}{2 L}}\right) = pK_a + \log(1) = pK_a[/tex]

How is this setup giving the wrong answer as opposed to recalculating [H3O+] after the dilution?
 
Chemistry news on Phys.org
  • #2
It looks like x moles/x moles=1 is the error. It should look more like X mol per L/Y mol per L or (.10 M/.12 M), when X=.10, Y=.12 and M=(mol/L).

Due to the common ion effect and Le Chatelier's principal, the weak electrolyte ionizes less than the strong electrolyte. Therefore the equilibrium shifts in favor of the strong electrolyte, creating an unequal molar concentration of acid and base (example .10 M and .12 M). Hopefully I got the question right.
 
  • #3
A hint; take a look at the derivation of the HH equation and the simplifying assumptions that are made...

On the surface definition of a buffer, the pH is largely defined by pKa and has a broad largely unchanged pH over a range defined by the buffer's capacity. Dilution of the buffer only changes the capacity but not the pH range to the first order approximation.

In reality, the quantities used are not the formal concentrations of the corresponding acid and conjugate, but their Activities which do have a bearing on changing the pH as one changes concentration.

Borek's pH calculator (chembuddy) uses Debye Huckel and Extended Debye Huckel Limiting Law to make better approaches to an iterative solving of the pH in buffers and titrations. He has a good explanation on the web site.
 

FAQ: Why does the pH of a diluted solution change?

What is the PH of a diluted solution?

The pH of a diluted solution refers to the measure of its acidity or alkalinity on a scale of 0-14. A pH of 7 is considered neutral, below 7 is acidic, and above 7 is alkaline.

How is the pH of a diluted solution calculated?

The pH of a diluted solution is calculated by taking the negative logarithm of the hydrogen ion concentration in moles per liter. This can be expressed as pH = -log [H+].

Why is the pH of a diluted solution important?

The pH of a diluted solution is important because it affects the chemical and biological processes that occur within the solution. It also determines the solubility and reactivity of certain substances.

How does dilution affect the pH of a solution?

Dilution of a solution can affect its pH by changing the concentration of hydrogen ions. As the solution becomes more diluted, the concentration of hydrogen ions decreases, resulting in a higher pH.

What factors can influence the pH of a diluted solution?

The pH of a diluted solution can be influenced by various factors, such as the initial concentration of the solution, the strength of the acid or base being diluted, and the type of solvent used for dilution.

Similar threads

Back
Top