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- Does the SVP of water vapor depend on external pressure (eg atmospheric pressure)?
Suppose you have a container of water at a given temperature T (say normal room temperature) with a vacuum above it. Presumably water will evaporate until there is sufficient vapor that the pressure of it above the water is the SVP for that temperature.
Now suppose that there is air above the water in a closed system. Is the pressure of the water vapor the same as in the former case? I really don't understand this, because on a phase diagram it would seem that given the pressure of the atmosphere is greater than the SVP of water, and therefore that the vapor, also under the same pressure from the air, cannot be in equilibrium with the water.
Now suppose that there is air above the water in a closed system. Is the pressure of the water vapor the same as in the former case? I really don't understand this, because on a phase diagram it would seem that given the pressure of the atmosphere is greater than the SVP of water, and therefore that the vapor, also under the same pressure from the air, cannot be in equilibrium with the water.