- #1
Noir
- 27
- 0
Homework Statement
When 520nm light falls on a metal, the current through the circuit is brought to zero by a reverse voltage of 1.13V. What is the threshold frequency for this metal.
Homework Equations
E = h.f
The Attempt at a Solution
Using the above formula I get an threshold frequency of 2.72 x 10^14 Hz. Except here's my question, the reverse voltage doesn't have anything to do with the work function if it brings the current down to zero. Or does it, can someone please explain the process? I'm just confused by the term reverse voltage, or stopping voltage.
Thanks for any help :)