Photon Energy Level: Why Green Light Falls Greater Energy Levels

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Electrons are excited to higher energy levels and emit photons when they fall back to lower levels. Green light, with a wavelength of 5.58 x 10^-7 m, has a shorter wavelength than red light at 6.48 x 10^-7 m, resulting in higher energy per photon. The relationship between energy and wavelength is defined by the equations E = hf and E = hv/λ, indicating that shorter wavelengths correspond to greater energy. Thus, when photons from green light are emitted, they represent a transition from a higher energy level to a lower one, which is greater than that of red light. This confirms that green light photons possess more energy than red light photons.
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I understand that electrons are excited to higher energy levels. When they fall back levels, photons are emitted.

If green light has wavelength 5.58 \times 10^{-7}m and red light has wavelength of 6.48 \times 10^{-7}m, why is it that when a photon is emitted from green light, it falls a greater energy level?
 
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What is the relationship between energy and wavelength for electromagnetic waves?
 
v = f \lambda
E = hf = \frac{hv}{\lambda}

So green light has a smaller wavelength hence a larger value of energy. Is this why it falls a greater energy level?
 
Yes, that is so.
 
Air said:
v = f \lambda
E = hf = \frac{hv}{\lambda}

So green light has a smaller wavelength hence a larger value of energy. Is this why it falls a greater energy level?

so... if E=hf, green light have more energy than red light?
 
Yes, but that energy is per photon.
 

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