Photon Momentum and Energy: A Smooth Transition to a Tardyon's Properties?

[nakurusil]

What nakurusil does not understand is that my intention was to show that
p=gp'(1+V/u') (1)
E=gE'(1+Vu'/cc) (2)
in the case of a tardyon
and
p=gp'(1+V/c) (3)
E=gE'(1+V/c) (4)

in the case of a photon could be an illustrations of the fact that the formula which accounts for an effect generated by a photon can be obtained from the corresponding formula that accounts for a simillar effect generated by a tardyon by simply replacing u=u'=c.

...and everybody that answered to you said that you shouldn't attempt that since it is incorrect. We also tried to correct you by showing how you can get the right derivation starting from:

$$p=\gamma(p'+\beta E'/c)$$

by using $$E=p'c$$

I did not find in the literature an explicit mentioning of the fact that the functions (1+V/u') and (1+Vu'/cc) have the same limit for u' going to c.

...and this is for good reason, no self-respecting book would show such an incorrect approach, two or three of us tried to explain this to you.

 

[bernhard.rothenstein]

photon tardyon

...and everybody that answered to you said that you shouldn't attempt that since it is incorrect. We also tried to correct you by showing how you can get the right dericvation startig from:

$$p=\gamma(p'+\beta E'/c)$$

by using $$E=p'c$$




...and this is for good reason, two of us tried to explain this to you.

As I see you use the plural (we) showing that you do not conspect all the answers: see the competent answer of robphy who considers that the equations are at least mathematically correct. Who are the two?
You did not explain why the statement concerning the transition from the properties of a tardyon to the properties of a photon simply stating no. Could you extend your oppinion?