- #1
birulami
- 155
- 0
Photons with smaller and smaller wave lengths have a higher and higher energy and these engeries have an increasing Schwarzschild radius [itex]r_s[/itex]. Consequently i can ask when half the wave length [itex]\lambda/2[/itex] is equal to [itex]r_s[/itex], such that one wave length fits into the sphere of the Schwarzschild radius.
I did the calculation and came out with [tex]\lambda/2 = r_s = \sqrt{Gh/c^3} =\sqrt{2\pi}l_p[/tex] where [itex]l_p[/itex] is the Planck length. Incidently the mass of this photon is [itex]\sqrt{2\pi}\,m_p[/itex] with [itex]m_p[/itex] being the Planck mass.
Now I wonder. Should I be at least a bit surprised about such extremely simple formulas or not. To put another way, is this as trivial as transforming [itex]ab=1[/itex] into [itex]a=1/b[/itex], or is there at least one physical statement needed between the Schwarzschild radius and this specific photon wave length? (Hmm, I hope someone can understand what I mean here.
)
I did the calculation and came out with [tex]\lambda/2 = r_s = \sqrt{Gh/c^3} =\sqrt{2\pi}l_p[/tex] where [itex]l_p[/itex] is the Planck length. Incidently the mass of this photon is [itex]\sqrt{2\pi}\,m_p[/itex] with [itex]m_p[/itex] being the Planck mass.
Now I wonder. Should I be at least a bit surprised about such extremely simple formulas or not. To put another way, is this as trivial as transforming [itex]ab=1[/itex] into [itex]a=1/b[/itex], or is there at least one physical statement needed between the Schwarzschild radius and this specific photon wave length? (Hmm, I hope someone can understand what I mean here.