- #1
zellwwf
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Hello PF people,
In a Compton scattering event, after the collision, the Photon has an energy of 0.12 MeV
and the Electron has an energy of 0.04 MeV. Find the following:
i) The Wavelength of the photon before the collision.
ii) The scattering angle for the photon after the collision.
iii) The scattering angle for the electron after the collision.
1 . Conservation of Energy
2 . Conservation of Momentum
3 . Compton's Scattering [itex]Δλ = \frac{h}{mc}(1-cos(θ))[/itex]
I tried to equate the conservation of energy,
i get a negative energy for the photon before it collides:
E_p + E_e = E_p + E_e
Then substituting (in MeV):
X + 0.511 = 0.04 + 0.12 --> X = -0.351 MeV
I did not copy anything wrong, the problem sheet gives these numbers, what do i do? is this wrong or should i continue?
Homework Statement
In a Compton scattering event, after the collision, the Photon has an energy of 0.12 MeV
and the Electron has an energy of 0.04 MeV. Find the following:
i) The Wavelength of the photon before the collision.
ii) The scattering angle for the photon after the collision.
iii) The scattering angle for the electron after the collision.
Homework Equations
1 . Conservation of Energy
2 . Conservation of Momentum
3 . Compton's Scattering [itex]Δλ = \frac{h}{mc}(1-cos(θ))[/itex]
The Attempt at a Solution
I tried to equate the conservation of energy,
i get a negative energy for the photon before it collides:
E_p + E_e = E_p + E_e
Then substituting (in MeV):
X + 0.511 = 0.04 + 0.12 --> X = -0.351 MeV
I did not copy anything wrong, the problem sheet gives these numbers, what do i do? is this wrong or should i continue?