Physics 101: Average Force Calculation for a Falling Object Hitting a Pole

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In summary, an object with a mass of 200kg falls from a height of 10m and hits a pole, causing the pole to go 8cm into the ground. To find the average force of the pole's descent into the ground, we can use the equation E(p) = mgh. By plugging in the values, we get an answer of 15712J or 15.7KJ. Additionally, we can use the equation W = F*d to find the force, which is equal to the difference in kinetic energy. The force is equal to the mass (200kg) multiplied by gravity (9.82m/s^2), which gives us a force of 1964N. Therefore,
  • #1
Okki2
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Homework Statement



200kg object 10m in the sky falls 8 meters and hits a pole. pole goes 8cm into ground.

Homework Equations


Average Force for the poles descent into the ground (8cm). Answer in Newtons.


The Attempt at a Solution



E(p) = mgh = 200*9.82*8J = 15712J = 15.7KJ

hmmm...
 
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  • #2
How much do you know about the concept of work?
 
  • #3
W=F*S

F = mg = 200*9.82 = 1964N

W = 1964N*8M = 15712N ?

hmm..im not getting the right answer.
 
  • #4
Yes, work = force * distance. There's also a relationship that says that work = difference in kinetic energy. If you can find the amount of potential energy that's been made into kinetic energy during the fall, you can find the amount of kinetic energy lost when the object pushes the pole down, which is then equal to the work done.

The force in W = F*d is the one you want to find. And the unit of work is not, as you say in your previous post, Newton. It's Joules :)
 

FAQ: Physics 101: Average Force Calculation for a Falling Object Hitting a Pole

What is Physics 101: Average Force Calculation for a Falling Object Hitting a Pole?

Physics 101 is an introductory course in physics that covers basic concepts and principles, including the calculation of average force for a falling object hitting a pole. This calculation involves using Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

How is average force calculated for a falling object hitting a pole?

To calculate the average force for a falling object hitting a pole, you will need to know the mass of the object, the height at which it is dropped, and the time it takes to reach the ground. The formula for average force is force = mass x acceleration, where acceleration is equal to the change in velocity divided by the change in time.

What is the significance of calculating average force for a falling object hitting a pole?

Calculating average force for a falling object hitting a pole can help us understand the impact and potential damage caused by the object. It also allows us to make predictions and take precautions to prevent accidents or injuries.

Can average force be negative?

Yes, average force can be negative. A negative average force means that the object is accelerating in the opposite direction of its initial velocity. For example, if a ball is thrown upwards, the force of gravity will cause it to slow down and eventually reverse direction, resulting in a negative average force.

Are there any limitations when calculating average force for a falling object hitting a pole?

Yes, there are some limitations when calculating average force for a falling object hitting a pole. This calculation assumes that the object is falling in a vacuum with no other forces acting on it, which is not always the case in real-world scenarios. Additionally, the calculation does not take into account factors such as air resistance, which can affect the object's acceleration and overall impact on the pole.

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