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gdhillon
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Q:A sandbag stops a 12 g bullet which was traveling at 860 m/s. The bullet penetrated a
distance of 24 cm into the sand?
a) How long did it take the bullet to stop?
b) What average force acted on the bullet?
first i used ∇p=Ft so 10.32=18490t t=5.6*10^-4 sec
then i put that into e=1/2mv^2 (to get letter A) so 1/2(.012)860^2= 4437.6
distance of 24 cm into the sand?
a) How long did it take the bullet to stop?
b) What average force acted on the bullet?
first i used ∇p=Ft so 10.32=18490t t=5.6*10^-4 sec
then i put that into e=1/2mv^2 (to get letter A) so 1/2(.012)860^2= 4437.6
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