Physics 12 energy, work question

In summary, a sandbag stopped a 12 g bullet traveling at 860 m/s and penetrating 24 cm into the sand. To find the time it took for the bullet to stop, the equation ∇p=Ft was used, resulting in a time of 5.6*10^-4 seconds. Using the formula e=1/2mv^2, the average force acting on the bullet was calculated to be 4437.6. However, the data provided does not give enough information to calculate the initial force or time, so additional equations were needed.
  • #1
gdhillon
16
0
Q:A sandbag stops a 12 g bullet which was traveling at 860 m/s. The bullet penetrated a
distance of 24 cm into the sand?
a) How long did it take the bullet to stop?
b) What average force acted on the bullet?
first i used ∇p=Ft so 10.32=18490t t=5.6*10^-4 sec
then i put that into e=1/2mv^2 (to get letter A) so 1/2(.012)860^2= 4437.6
 
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  • #2
gdhillon said:
first i used ∇p=Ft so 10.32=18490t
Where did the 18490 come from? The data tells you neither F nor t, only distance.
 
  • #3
You know the distance traveled by the bullet, it's initial velocity, and it's final velocity. Use a kinematics equation which relates them to find out the acceleration of the bullet. Now use that to find the time it travels for using another kinematics equation. And then use that to calculate the average force using the formula you wrote.
 

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