- #1
gdhillon
- 16
- 0
:An object explodes into three equal masses. One mass moves East at a velocity of 15.0
m/s. If a second mass moves at a velocity of 10.0 m/s 45.0 South of East, what is the
velocity of the third mass?
I drew these vectors tip to tail, then used cos law to determine the velocity vector of the first mass, c^2=a^2+b^2-2abcosC...subing in numbers i got c^2=15^2+10^2-2(15)(10)cos45
c^2=325-300cos45= 10.625. then by using sin law i got the angle. sin45/10=sinc/10.239 giving me 11m/s @49 degrees S of E
m/s. If a second mass moves at a velocity of 10.0 m/s 45.0 South of East, what is the
velocity of the third mass?
I drew these vectors tip to tail, then used cos law to determine the velocity vector of the first mass, c^2=a^2+b^2-2abcosC...subing in numbers i got c^2=15^2+10^2-2(15)(10)cos45
c^2=325-300cos45= 10.625. then by using sin law i got the angle. sin45/10=sinc/10.239 giving me 11m/s @49 degrees S of E