Physics distance and acceleration Problems

In summary: The correct answer is a=0.46 m/s^2 and x=500m.In summary, Marcus's car has an acceleration of 0.46 m/s^2 and travels a distance of 500m after overtaking Melissa's car in 12 seconds.
  • #1
Dhooy7
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Homework Statement



What acceleration does Marcus feel and how long does Marcus travel with the details: Marcos and Melissa are driving. Marcus's car travels 21 m/s and Melissa's travels 25 m/s. Marcus's car is 200 m behind Melissa's car when he hits the gas, giving constant acceleration. Marcus overtakes 12 sec?

Homework Equations

The Attempt at a Solution

 

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  • #2
Dhooy7 said:

Homework Statement



What acceleration does Marcus feel and how long does Marcus travel with the details: Marcos and Melissa are driving. Marcus's car travels 21 m/s and Melissa's travels 25 m/s. Marcus's car is 200 m behind Melissa's car when he hits the gas, giving constant acceleration. Marcus overtakes 12 sec?

Homework Equations

The Attempt at a Solution


Welcome to the PF.

Those images are really hard to see. Can you please type your solution into the forum, so it is easier for us to help you? Thanks.
 
  • #3
It is far preferable that you type details of your method and working, so respondants can read it easily and quote parts of it in their reply.

Presumably you post here hoping for assistance? So ... by making that effort you'll make it easy for people to help you.

I see you are new here so , http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif
 
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  • #4
I got delta x=285.12 m
a=0.46

I did it another way with someone else and he said a=3.44 m/s and x=500m. Not sure which is right.
 
  • #5
Mellia=Marcu's distance +200m.

I used vf2=vo2+2a (200m) and solved for a.
vf=25
vo=21
t=12

Then used delta x =vot+1/2at2
 
  • #6
Mellia=Marcu's distance +200m
Check this. Whose car will travel the greatest distance after we start observing them?

Your equation seems to be solving for Marcu's car to attain 25 m/s when it reaches Mellia's starting point (being 200m from where he started).
EDITED
 
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  • #7
So what is the right answer?
 
  • #8
Your working is not correct. Try drawing a clear diagram that fits the scenario you are examining.
 
  • #9
So neither of these are correct:

a=3.44 m/s and x=500m.

I got delta x=285.12 m
a=0.46
 

FAQ: Physics distance and acceleration Problems

What is the equation for calculating distance in physics?

The equation for calculating distance in physics is d = vt, where d is distance, v is velocity, and t is time.

How do you calculate acceleration in physics?

Acceleration is calculated using the equation a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

What is the difference between distance and displacement in physics?

Distance is the total length of a path traveled by an object, while displacement is the straight line distance between an object's starting point and ending point. In other words, displacement takes into account direction, whereas distance does not.

How does time affect distance and acceleration?

Time is directly related to both distance and acceleration. In the equation d = vt, distance is directly proportional to time. This means that as time increases, distance also increases. In the equation a = (vf - vi) / t, acceleration is inversely proportional to time. This means that as time increases, acceleration decreases.

What is the difference between average and instantaneous acceleration?

Average acceleration is the change in velocity over a period of time, while instantaneous acceleration is the acceleration at a specific moment in time. Average acceleration is calculated using the equation a = (vf - vi) / t, while instantaneous acceleration is calculated using the derivative of the position-time graph.

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