Physics gr11 review (acceleration)

In summary, the first problem involves a train accelerating uniformly from rest and finding the speed of the last car as it passes a railway worker. The second problem involves calculating the time it takes for a dropped can of pop to reach the ground from a hot air balloon. The third problem involves finding the distance between two stones dropped from a building at different times. The last problem involves finding the height of a sea cliff based on the time it takes for a rock to hit the ocean and the speed of sound. Various equations are used to solve these problems.
  • #1
justme_girl04
2
0
1. The problem statements, all variables and given/known data

1. a 100m long train accelerates uniformly from rest. If the front of the train passes a railway worker 150m down the track at a speed of 25m/s, what will be the speed of the last car as it passes the worker?

2. a hot air baloon is rising up with a constant velocity of 4m/s. As the balloon reaches a height of 4m above the ground the balloonist accidentally drops a can of pop over the edge of the basket. How long does it take the pop can to reach the ground?

3.a stone is dropped from the roof of a high building. a second stone is droped 1s later. How far apart are the stones when the second one reached the speed of 23m/s?

3. a rock is dropped from a seacliff and the sound of it stirking the ocean is heard 3s later. If the speed of sound is 330m/s, how high is the cliff?



Homework Equations


These are the equations we were given to solve the questions:
(it might look messy, f is final and t is time)
Vf^2=V1+2ad
Vf=V1+at
d=V1+1/2at^2
d=Vft-1/2at^2
d=(V1+Vf/2)t

honestly i tried doing these, but i just don't get it!
 
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  • #2
1. 150/25 = 250/x
x = 41.6666667m/s

2. this one is weird. can't help. are you sure you copied all the data?

3. vf^2=vi+2ad
23^2=0+2(9.8)d
d=27 m (stone 1)

d = (vi+vf/2)t
27 = (0+ 27/2)t
t=2 seconds( the first stone reached 27m in two seconds)

2s -1s = 1s so we want to calculate the position of stone 2 at one seconds so

d = vi + .5at^2
d = 0 + .5*9.8*1^2
d = 4.9m

21 - 4.9 = 22.1m difference

4. 3s * 330m / 1s = 990 m

have no clue if any of these are correct. please check my work guys
 
  • #3
Hey thanks for the help, the first and third make sense.. yea it know the second is weird but i read the question over and that's what it says. the 4th one is way off lol, it was a pretty long solution that came to a heights of h=4.9(2.9)^2
 

FAQ: Physics gr11 review (acceleration)

What is acceleration and how is it different from velocity?

Acceleration is the rate of change of velocity over time. While velocity measures the speed and direction of an object, acceleration measures how quickly an object is changing its velocity. In other words, acceleration determines how much an object's velocity is changing per unit of time.

How is acceleration calculated?

Acceleration is calculated by dividing the change in velocity by the change in time. The formula for acceleration is a = (v2 - v1) / (t2 - t1), where v2 and v1 are the final and initial velocities, and t2 and t1 are the final and initial times.

What are the units of acceleration?

The SI unit for acceleration is meters per second squared (m/s²). Other common units for acceleration include feet per second squared (ft/s²) and kilometers per hour squared (km/h²).

How does acceleration affect an object's motion?

Acceleration can either increase or decrease an object's velocity, depending on the direction of the acceleration. If the acceleration is in the same direction as the velocity, the object's speed will increase. If the acceleration is in the opposite direction, the object's speed will decrease. In the case of uniform acceleration, the object's velocity will change by the same amount every second.

What are some real-life examples of acceleration?

Acceleration can be observed in many everyday situations, such as a car speeding up or slowing down, a roller coaster going up or down a hill, and a person jumping off a diving board. In sports, acceleration is also seen when a pitcher throws a baseball, a sprinter starts a race, or a skater spins faster. In all of these examples, the object's velocity is changing over time, resulting in acceleration.

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