Physics Hwk. Problem: Center of Mass

In summary, the spaceship is coasting at a velocity of +250 m/s and carries rockets that are mounted in firing tubes. The mass of the rocket is 1200 kg and the mass of the spaceship is 2.0*10^6 kg. The firing of the rocket brings the spaceship to a halt, leaving the rocket with a velocity of 500300000/1200 = 416916.67 m/s. The equation used to solve this problem is vcm=m1*v1+m2*v2 divided by m1+m2, with the assumption that the center of mass is not a factor in this scenario.
  • #1
shawonna23
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0
With the engines off, a spaceship is coasting at a velocity of +250 m/s through outer space. The ship carries rockets that are mounted in firing tubes, the back ends of which are closed. It fires a rocket straight ahead at an enemy vessel. The mass of the rocket is 1200 kg, and the mass of the spaceship (not including the rocket) is 2.0*10^6 kg. The firing of the rocket brings the spaceship to a halt. What is the velocity of the rocket?

I used the equation vcm=m1*v1+m2*v2 divided by m1+m2. The answer I got is wrong. Am I using the right equation? Please Help ASAP!
 
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  • #2
The initial mass of the rocket, spaceship combination is 2001200 kg and its speed is 250 m/s so its momentum is 500300000 kgm/s. The momentum of the spaceship after firing the rocket is 0 so its momentum then is 0. The momentum of the rocket is
1200vr and that must equal the original total momentum:

1200vr= 500300000.

I have no idea why you are using "vcm" since the problem does not say anything about the center of mass!
 
  • #3


Yes, you are using the correct equation for center of mass. However, it seems like you may have made a mistake in your calculation. The final velocity of the spaceship after firing the rocket should be zero, as it comes to a halt. This means that the equation should be set up as 0 = (2.0*10^6 kg)(250 m/s) + (1200 kg)(v2) / (2.0*10^6 kg + 1200 kg). Solving for v2, the velocity of the rocket, gives a value of approximately 104.17 m/s. Double check your calculations to see if you made any errors. Also, make sure to pay attention to the units and use consistent units throughout your calculation. Good luck!
 

FAQ: Physics Hwk. Problem: Center of Mass

What is the definition of center of mass in physics?

The center of mass is a point in an object or system that behaves as if all of the mass is concentrated at that point. It is the point at which external forces act on the object, causing it to move in a straight line with constant velocity.

How is the center of mass calculated?

The center of mass can be calculated using the formula: xcm = (m1x1 + m2x2 + ... + mnxn) / (m1 + m2 + ... + mn), where xcm is the position of the center of mass, m is the mass of each individual part, and x is the position of each individual part along the chosen axis.

What is the significance of the center of mass in physics?

The center of mass is important in physics because it helps us understand the motion of objects and systems. It allows us to simplify complex systems and treat them as if all of the mass is concentrated at a single point. It also helps in analyzing the stability and balance of objects and predicting their movements.

Can the center of mass be outside of an object?

Yes, the center of mass can be located outside of an object. This is often the case for irregularly shaped objects or objects with asymmetrical mass distributions. As long as the external forces act on the object at the center of mass, it will behave as if all of its mass is located at that point.

How does the center of mass affect rotational motion?

The center of mass plays a crucial role in rotational motion. When an external force acts on an object at its center of mass, it will cause the object to rotate around that point. This is known as pure rotational motion. Additionally, the center of mass is used to determine the moment of inertia, which is a measure of an object's resistance to rotational motion.

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