Physics Lab question velocity/Δt simple

In summary: in summary, the time between the bands on the falling object is getting shorter, as the object speed up.
  • #1
munchy35
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Homework Statement



Hi all. I did a lab in physics and am struggling with a question. The lab involved dropping an object that had clear and black bands on it through a photogate to determine velocity and time.

The question I'm struggling with is...

Looking at the RAW DATA, you should notice that the Δt values are getting smaller as the falling proceeds. Why is this?

Homework Equations



There aren't really equations. It's just a question, but attempted answer below.


The Attempt at a Solution



I'm just confused on what this means. I'm pretty sure Δt is the time for which the photgate was open - between the bands on the falling object. Is the answer simply that the Δt becomes smaller, because as the object falls the velocity is increasing - so the time that the photogate was open will become shorter.

Is this right? If it is, can someone help me use clearer wording. Thanks!
 
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  • #2
munchy35 said:
I'm just confused on what this means. I'm pretty sure Δt is the time for which the photgate was open - between the bands on the falling object. Is the answer simply that the Δt becomes smaller, because as the object falls the velocity is increasing - so the time that the photogate was open will become shorter.

Is this right? If it is, can someone help me use clearer wording. Thanks!

Yes. As the object speeds up, the time for a band to pass the photogate becomes shorter.
 
  • #3
munchy35 said:


The Attempt at a Solution



I'm just confused on what this means. I'm pretty sure Δt is the time for which the photgate was open - between the bands on the falling object. Is the answer simply that the Δt becomes smaller, because as the object falls the velocity is increasing - so the time that the photogate was open will become shorter.

Is this right? If it is, can someone help me use clearer wording. Thanks!


Looks good to me..
 

FAQ: Physics Lab question velocity/Δt simple

What is the equation for velocity in a physics lab experiment?

The equation for velocity is v = Δx/Δt, where v is velocity, Δx is the change in position, and Δt is the change in time.

How do you calculate the average velocity in a physics lab experiment?

To calculate average velocity, divide the total displacement by the total time taken. This can be represented by the equation v_avg = (xf - xi)/(tf - ti), where v_avg is the average velocity, xf is the final position, xi is the initial position, tf is the final time, and ti is the initial time.

What is the difference between speed and velocity?

Speed is a scalar quantity that represents the rate at which an object is moving. Velocity is a vector quantity that not only represents the rate of motion, but also the direction of the motion.

How does the slope of a position-time graph relate to velocity?

The slope of a position-time graph represents the change in position divided by the change in time, which is the definition of velocity. Therefore, the slope of a position-time graph is equal to the velocity of the object.

How does the direction of motion affect velocity?

The direction of motion is an important component of velocity. If an object is moving in a straight line, the velocity will be positive if it is moving in the positive direction and negative if it is moving in the negative direction. If an object is moving in a curved path, the velocity will be constantly changing direction and magnitude, making it a vector quantity.

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