Physics of Spring with Electrostatics

In summary, the problem at hand is a 3-body problem, with a projectile of mass m and a target made up of two atoms of mass M/2 connected by a spring. The projectile is sent towards the target and a second force causes the target to reflect the projectile. The question is asking for the subsequent motion of the three bodies. The system involves both an internal spring, with force F = -kx, and an electrical force, with force F = kQq/r^2, between the similarly charged particles. The target's motion will depend on the speed of the projectile and the distance it travels before being repelled. The problem can be solved using conservation of energy and momentum.
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Homework Statement


Consider a simple 3-body problem in one dimension. One body (the projectile) has mass m. The second body (the target) is made up of two "atoms" each of mass M/2 (total mass = M). Assume an internal spring holds the two atoms together. If the projectile is sent toward the target and a second force makes the target reflect the projectile, what is the subsequent motion of the three bodies?


Homework Equations


F (spring) = -kx
F (electrical) = kQq/r^2


The Attempt at a Solution


The "second force" is an electrical force, i.e. the three particles are similarly charged. To simplify things, I will consider a lengthless and massless spring and ignore frictional forces. The question also implies that energy is not conserved between the projectile and the target (but the target system itself conserves energy).

I was thinking that as the projectile approaches the target with an initial speed (by Newton's First Law, speed should be constant because there are no external forces acting on it), the electrical force between the target and the projectile strengthens (due to an inverse relationship between electrical force, F, and distance, r, [F = kQQ/r^2]). As this occurs, the target is repelled by the projectile (from rest to an initial speed) and causes the nearest atom to compress the spring (because the projectile's electrical force on the farthest atom is weaker), causing the spring to gain potential energy [F = -kx]. Within the target, the potential energy of the spring will be converted into kinetic energy by bouncing back and forth with the two attached atoms, acting with and against the electrical force between the two atoms. Depending on the speed of the projectile, the distance the target travels before the projectile is repelled will differ (because the target is free to move).

Does the spring take the kinetic energy of the target or does the target continue to move indefinitely in space (by Newton's First Law)?
Does the spring eventually reach equilibrium due to the balance of electrical forces between the two attached atoms (which are similarly charged)?

Thanks, any help will be appreciated!
 
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  • #2
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This looks like a conservation of energy and momentum problem. It would seem the projectile imparts some of its kinetic energy to one of the target masses initially.

Can you calculate the velocities of the projectile and target mass right after this collision? Express the answer in terms of m, M, and the projectile's initial velocity v0.
 
  • #3
The question asks more for a qualitative solution to the problem (i.e. determining the physics behind the problem and using physics logic to determine a general approximation of the motion of the system).

I originally thought that the "collision" conserves kinetic energy, but would it also be possible that the transferred kinetic energy from the projectile is held within the spring? If this is the case, wouldn't the mass eventually slow down because it loses kinetic energy? Or would the mass continue to move at a slower speed?

Sorry for the questions, I'm just a little lost about the physics behind the interactions. All I know is that a spring can convert the kinetic energy into potential energy, but would that potential energy be released back into kinetic energy to move the attached masses?

What I'm trying to say is:

O||||||O <-- O

<- O||||||O <-- O

<-- O|||||O O
(the point where the electrical force of the spring system repels the projectile; the spring is compressed)

<-- O|||O O -->

...and then the spring system either continues to move leftwards with a constant velocity while the spring undergoes harmonic motion or the spring system slows down while the spring's harmonic motion slows down.
 

FAQ: Physics of Spring with Electrostatics

What is the physics behind a spring with electrostatics?

The physics of a spring with electrostatics involves the principles of electrostatics and mechanics. When an electric charge is applied to a spring, it creates an electric field that can exert a force on other charges. This force can cause the spring to stretch or compress, depending on the direction of the applied charge. The amount of stretching or compression is determined by the spring constant, which is a measure of the stiffness of the spring.

How does the electric charge affect the behavior of the spring?

The electric charge applied to the spring creates an electric field that exerts a force on the charges within the spring. This force can cause the spring to stretch or compress, depending on the direction of the applied charge. The amount of stretching or compression is determined by the spring constant, which is a measure of the stiffness of the spring.

What is the relationship between the electric charge and the spring constant?

The electric charge and the spring constant have a direct relationship. A higher electric charge will result in a stronger electric field and a larger force exerted on the spring, leading to a greater amount of stretching or compression. On the other hand, a higher spring constant means the spring is stiffer and will require a greater force to produce the same amount of stretching or compression.

Can the electric charge on a spring be changed?

Yes, the electric charge on a spring can be changed by altering the amount of charge applied to it. This can be done through various methods such as using a battery or a power supply to apply a specific amount of charge to the spring. The charge can also be changed by changing the distance between the spring and another charged object.

How is the behavior of a spring with electrostatics different from a regular spring?

A spring with electrostatics behaves differently from a regular spring because it is affected by the electric field created by the applied charge. This means that in addition to the force exerted by the spring constant, there is an additional force acting on the spring due to the electric charge. This can result in a non-linear relationship between the applied force and the resulting displacement of the spring.

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