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student54321
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Physics Projectile Launched at Angle. HELP, TEST TODAY IN 2 HOURS!
An object is launched from the top of a building
with an initial velocity of 15 m/s [32 degrees]. If the
building is 65.0 m high, how far from the base
of the building will the object land?
dx = vix (t)
dy=viy(t) + 1/2a (t)^2
First I drew a diagram. Then set up the x and y table:
The variables I know; vix= 12.72 (which I got from vicos(theta), viy= 7.948, ay=-9.81, ax=0.
Then I solved the time for the 32 degrees. Then I solved the time for the other part and then I solved for dx, I got 66.9 m.
The answer in the book says its 58 m.
Can't figure out how to do this, help please!
Homework Statement
An object is launched from the top of a building
with an initial velocity of 15 m/s [32 degrees]. If the
building is 65.0 m high, how far from the base
of the building will the object land?
Homework Equations
dx = vix (t)
dy=viy(t) + 1/2a (t)^2
The Attempt at a Solution
First I drew a diagram. Then set up the x and y table:
The variables I know; vix= 12.72 (which I got from vicos(theta), viy= 7.948, ay=-9.81, ax=0.
Then I solved the time for the 32 degrees. Then I solved the time for the other part and then I solved for dx, I got 66.9 m.
The answer in the book says its 58 m.
Can't figure out how to do this, help please!
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