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Homework Statement
In the transformer shown in the figure below, the load resistance RL is 46.0 Ω. The turns ratio N1/N2 is 2.65, and the rms source voltage is ΔVS = 85.0 V. If a voltmeter across the load resistance measures an rms voltage of 27.5 V, what is the source resistance Rs?
I've attached an image of the circuit diagram.
The answer is 194 Ohms
Homework Equations
Vprimary/Vsecondary = Isecondary/Iprimary = Nprimary/Nsecondary
ΔV=IR
The Attempt at a Solution
I've found the current through each loop.
Loop 2: VL/RL = 27.5/46 = .5978 Amps
Loop 1: I2/I1 = N1/N2.... so, .5978/2.65 = .2256 Amps
Here is where I have problems. Can I apply Kirchoff's loop rule to loop 1 (V - Vresistor (=IR) - Vinductor = 0)? And if so, how do I go about finding the potential difference over the large inductor?