- #1
cbarker1
Gold Member
MHB
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Hello Everybody,
A trapper walks a 6.2 km straight-line distance from the cabin to the lake, beginning to the lake has an angle of +45 degrees. Determine the east and north components of her dispacement vector.
Work:
E component: $6.2\times\cos\left({45^{\circ}}\right)$ = 4.38
N Component:$6.2\times\sin\left({45^{\circ}}\right)$=4.38
I have troubles to next question:
How many more kilometers would the trapper have to walk if she walked along the component displacements?
A trapper walks a 6.2 km straight-line distance from the cabin to the lake, beginning to the lake has an angle of +45 degrees. Determine the east and north components of her dispacement vector.
Work:
E component: $6.2\times\cos\left({45^{\circ}}\right)$ = 4.38
N Component:$6.2\times\sin\left({45^{\circ}}\right)$=4.38
I have troubles to next question:
How many more kilometers would the trapper have to walk if she walked along the component displacements?
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