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There is no angle give, everything that I have is in the picture.isukatphysics69 said:Is there an angle given? if not, maybe use those tiny dots and create a triangle and take the tangent inverse to find the angle. Then break the problem up into its x and y components
Alright. I got 114 for the whole bottom and 46 for the height. The max height would be at 114/2=57. Arctan(46/57)=38.904degisukatphysics69 said:Yes so i haven't looked closely but if those tiny dots are equivalent distances i.e 1 unit each then try finding the angle using the tangent inverse after creating a triangle somewhere.
How would I go about finding gravitational acceleration with an angle and initial velocity?isukatphysics69 said:Yes so i haven't looked closely but if those tiny dots are equivalent distances i.e 1 unit each then try finding the angle using the tangent inverse after creating a triangle somewhere.
That’s the angle from origin to peak, not the same as initial angle.G Lenny said:Alright. I got 114 for the whole bottom and 46 for the height. The max height would be at 114/2=57. Arctan(46/57)=38.904deg
hint: gravity points down use your coordinate axis and break up componentsG Lenny said:How would I go about finding gravitational acceleration with an angle and initial velocity?
I can't think what equations would give me max height in terms of theta and g and final position in terms of theta and g.Nathanael said:That’s the angle from origin to peak, not the same as initial angle.
Anyway I wouldn’t do it that way. I would say pretend the initial angle θ and gravity strength g are known, then answer two questions: What is the max height in terms of θ and g? What is the final position in terms of θ and g?
If you can solve those two questions, then equate them with 46 and 114 meters, then you will have two equations in two unknowns (θ and g) and so can solve for g.
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