Pion decay (tell me if I'm approaching it correctly)

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The discussion focuses on the decay of a neutral pion into two photons, with one photon traveling in the positive x-direction and the other in the negative x-direction. The participant attempts to solve for the pion's velocity using conservation of momentum but is advised that both conservation of momentum and conservation of energy equations are necessary for a complete solution. The relationship between the energies of the photons, E1 and E2, is given as E1 = n * E2, which introduces another variable into the equations. It is emphasized that the solution should yield the pion's velocity in terms of n, the speed of light, and the pion's rest mass, although the rest mass ultimately cancels out. The need for both conservation laws is highlighted to ensure all variables are accounted for in the calculations.
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Homework Statement



A neutral pion may decay into two photons. A particular pion is traveling along the x-axis when it decays into two photos, the first going directly along the +x axis, the second going directly back along the -x axis. The energy of the photons is measured and it is found that E1 is n times more energetic than E2. Find the velocity u of the pion.

Homework Equations



1) relativistic momentum = gamma *m*u where u is velocity, m is mass
2) momentum of a photon is h/wavelength = h*frequency/c (I'm denoting frequency by nu).

The Attempt at a Solution



I tried to do this using conservation of momentum. I'd like to know if my solution is correct.

Pi = Pf (via conservation of momentum for isolated system)

so

gamma*m*u = h*nu1/c - h*nu2/c (the minus sign accounts for the fact that the photons move in opposite directions along the x axis)

but as given above, E1 = n*E2, so

gamma*m*u = h*nu2 (n - 1)/c

Then I solved for u using algebra (I didn't forget about the u in gamma, I squared everything and solved for u afterwards).

Can that be right? Or am I thinking way too simplistically here?
 
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Hi quasar_4! :smile:

(have a nu: ν :wink:)

It's a bit difficult to tell without seeing your final calculations,

but it looks as if you haven't used a conservation of energy equation. :confused:

You need a conservation of momentum equation and a conservation of energy equation, just as in the Newtonian case (and ν needn't come into it). :wink:
 
hello, tiny-tim! :-D

I need both? Hmm, I thought that I could do it just with conservation of momentum OR conservation of energy. We only have one unknown, so two equations and one unknown! What am I missing here? Why do we need to use both the conserved quantities?

(It's been a long, long time since I took any sort of modern physics class... I feel like such a dork for not remembering this!) :redface:
 
There are three equations and three unknowns. The equations are

Momentum Conservation
Energy Conservation
E1=n E2

The unknowns are
u, E1 and E2.

Your answer should come out in terms of n, c and the rest-mass of the pion.
 
Actually, the rest-mass of the pion drops out.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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